To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.
A, rotated then reflected
Answer: C is the correct answer Lines r and s and lines t and u must be parallel.
Step-by-step explanation: the step by step explanation is the the lines that answer C says are parallel
Lines r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16.
Answer:
No solutions
Step-by-step explanation:
So putting that into an equation it equals
2k+8=(4k+14)÷2
Move the 2 to the other side.
2∙2k+8=4k+14
Simplify.
4k+8=4k+14
It doesn't make sense so No Solutions
The missing part is the proof ... hope it helped thank you you welcome have a frat day thanks bye adios amigo q to balls bin en too visa much's gracious yew me la peals pot too Ajax thanks yes what ever loll <span />