Find the product of (-8) and (-13)

1 answer:

4 0

To find this you can always use a calculator, if your teacher allows you to. Just remember to punch in the negative signs correctly and don't mistake them for subtraction signs. Also if you don't know what product means, that means the answer of a multiplication problem so for example 9 is the product of 3x3 or 5 is the product of 5x1. The answer to your question is 104. Maybe next time you can solve it on your own! :)

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Help me on question 14 please

Brums [2.3K]

What is question 14?

7 0

3 years ago

(25pts) Due soon! Help!

navik [9.2K]

Answer:

true

True

False

Step-by-step explanation:

a. The problem tells me that for every 3 parts of red paint, I have 8 parts of yellow paint. To find the ratio of 1 part of yellow paint I can write the following statement

For 8 parts of yellow paint ------------ 3 parts of red paint

1 part of yellow paint ------------- x

So $x=\frac{1 part of yellow paint * 3 parts of red paint }{8 parts of yellow paint}$

$x= \frac{3}{8} parts of red paint$

b, I have the following relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 3 I have left

3 * 3 parts of red paint -------- 8 * 3 parts of yellow paint

9 parts of red paint ---------- 24 parts of yellow paint

c.I have the same relationship

3 parts of red paint ----- 8 parts of yellow paint

If I multiply the entire expression by 1/2 I have left

3/2 parts of red paint -------- 8/2 parts of yellow paint

3/2 parts of red paint ---------- 4 parts of yellow paint

as 3/2 is different from 10, then the approach is false

d. observing the relation of part a,

For 3 parts of red paint ------------ 8 parts of yellow paint

1 part of red paint ------------- x

So $x=\frac{1 part of red paint * 8 parts of yellow paint }{3 parts of red paint}$

$x= \frac{8}{3} parts of yellow paint$ that is different than 3/8 parts of yellow paint, then the approach is false

6 0

4 years ago

Read 2 more answers

Given that AXB is complementary to both CYD and FZE, and mAXB = 36°, what is mCYD + mFZE?

anyanavicka [17]

Complementary angles always equal 90°
So here is how to find what mCYD + mFZE equal
mCYD + mFZE + mAXB
mCYD + mFZE + 36° = 90°
Subtract
mCYD + mFZE = 54°

7 0

3 years ago

What is the average rate of change <br>y - 3 = -12 (x + 4)

vagabundo [1.1K]

Answer:

$- 12x$