Question

Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.

Answer 1

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

$A=\dfrac{a+b}{2}h$

Where, $a,b$ are parallel sides and $h$ is the vertical distance between the parallel sides.

Putting $a=28.7, b=22.3,h=16$ in the above formula, we get

$A=\dfrac{28.7+22.3}{2}\times(16)$

$A=\dfrac{51}{2}\times 16$

$A=51\times 8$

$A=408$

Therefore, the area of the trapezium is 408 square cm.