The answer is C) 3/4
Let's analyze separately each of the traits:
Parental generation: AA x Aa
F1 generation: AA AA Aa Aa
So, all progeny will <span>phenotypically resemble the first parent.
</span>Parental generation: BB x bb
F1 generation: Bb Bb Bb Bb
So, all progeny will <span>phenotypically resemble the first parent.
</span>
Parental generation: Cc x Cc
<span>F1 generation: CC Cc Cc cc
</span>Only 3 (CC, Cc, Cc) out of 4 progeny will <span>phenotypically resemble the first parent.
The genotypes for first two traits will not affect </span>phenotypical resemblance to the first parent. So, it only counts the third trait, for which the chance to have progeny that <span>phenotypically resemble the first parent is 3/4.</span>
Dwayne Johnson, Also known a the Rock
Since hemophilia is an X-linked recessive disorder, the probability depends on the X alleles.
So, if father has dominant allele (H), the probability that a <span>female child would suffer from hemophilia (genotype: hh) is 0%, no matter of mother's genotype:
Father Mother
Parents: H x Hh
Daughter: HH or Hh
</span> Father Mother
Parents: H x HH
<span>Daughter: HH
</span>
Father Mother
Parents: H x hh
<span>Daughter: Hh or Hh
</span>
But, if the father has recessive allele, the probability that a <span>female child would suffer from hemophilia (genotype: hh) will depend on mother's genotype.
If mother is dominant homozygous, there will be 0% of possibility:
</span> Father Mother
Parents: h x HH
<span>Daughter: Hh
</span>
If mother is recessive homozygous, the possibility is 100%:
Father Mother
Parents: h x hh
<span>Daughter: hh
</span>
If mother is heterozygous, the possibility is 50%:
Father Mother
Parents: h x Hh
<span>Daughter: Hh or hh</span>
