To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.
Answer:
Q1 1000 1
3500 3.5
500 .5
75 .075
1 .001
x 1/1000x or .001x Q2 Y= 1/1000x
Step-by-step explanation:
just search up 1000 meters to 1 kilometer and go from there :)
since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=9 \end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20r%5E2%20h~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D3%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%283%29%5E2%289%29%5Cimplies%20V%3D81%5Cpi)
Answer:
If I'm correct, the answer is 1296.
Step-by-step explanation:
6 x 6 x 6 x 6 = 1296
Answer:
65 gallons per minute
Step-by-step explanation:
The total volume of the tank at any given time is given by the equation:
V(t) = 65t + 280
In order to find the rate of change of volume, we can simply differentiate this equation with respect to time. This will give us the rate of change of the volume or the rate at which water is being pumped into the tank.
Differentiating the above equation we get:
V'(t) = 65
So we can see that the rate at which water is being pumped into the tank is 65 gallons per minute