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Arte-miy333 [17]
3 years ago
14

Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

Step-by-step explanation:

First choose two points on the line,

Let the points are A and B.

From point A to B we are moving downwards by (5 - 1 = 4 units)

Therefore, Rise = -4

Horizontal distance between A and B = 2 units

Therefore, Run = 2

Since, slope of a line = \frac{\text{Rise}}{\text{Run}}

Slope = \frac{-4}{2}

          = -2

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The function f(x)=x^2 and its transformation f(x)=(x-k)^2 are shown below. What is the value of k?
Leto [7]

Answer:

<h2>f(x - k) = (x - k)²⇒ k = 5</h2>

Step-by-step explanation:

f(x) + n - shift the graph n units up

f(x) - n - shift the graph n units down

f(x - n) - shift the graph n units to the right

f(x + n) - shift the graph n units to the left

==============================================

Look at the picture.

The graph has been shifted 5 units to the right.

Therefore we have f(x - 5).

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3 years ago
68.76−5.23<br><br> A 16.46<br><br> B 18.53<br><br> C 63.53<br><br> D 73.99
Romashka [77]
The answer is 63.53 subtracts 5.23 from 68.76


6 0
4 years ago
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HELP PLEASE!!! ( VERY IMPORTANT TO LOOK AT THE PICTURE)<br><br> A. 9<br> B. 12<br> C. 15<br> D. 21
larisa [96]

Answer:

c

Step-by-step explanation:

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8 0
3 years ago
Solve the inequality 2(4x-3)&gt;-3(3)+5x
Sholpan [36]

Answer:

x > -1\\

Step by step explanation:

~~~~~2(4x-3) > -3(3)+5x\\\\\implies 8x-6 > -9+5x\\\\\implies 8x > -9+6+5x\\\\\implies 8x > -3+5x\\\\\implies 8x -5x > -3\\\\\implies 3x > -3\\\\\implies x > -\dfrac 33\\\\\implies x > -1

5 0
2 years ago
Examine the pattern in the powers of i you wrote in the table, and create a rule for finding the value of large powers of i. Jus
denpristay [2]
Let N be any integer. Then

i^N=\begin{cases}1&\text{if }N\equiv0\mod4\\i&\text{if }N\equiv1\mod4\\-1&\text{if }N\equiv2\mod4\\-i&\text{if }N\equiv3\mod4\end{cases}

In other words:

(1) If N is a multiple of 4, then i^N=1.

(2) If dividing N by 4 leaves a remainder of 1, then i^N=i, since i^N=i^{4n+1} for some integer n, and from (1) we know that i^{4n+1}=i^{4n}i=i (because, obviously, 4n is a multiple of 4).

(3) If instead you get a remainder of 2, then i^N=-1. This follows from (1) as well. i^N=i^{4n+2}=i^{4n}i^2=(1)(-1)=-1.

(4) Finally, if you get a remainder of 3, then i^N=i^{4n+3}=i^{4n}i^2i=(1)(-1)(i)=-i.
5 0
3 years ago
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