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Arte-miy333 [17]
3 years ago
14

Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

Step-by-step explanation:

First choose two points on the line,

Let the points are A and B.

From point A to B we are moving downwards by (5 - 1 = 4 units)

Therefore, Rise = -4

Horizontal distance between A and B = 2 units

Therefore, Run = 2

Since, slope of a line = \frac{\text{Rise}}{\text{Run}}

Slope = \frac{-4}{2}

          = -2

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Ivahew [28]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
Chapter 9 TRP 9-1 Assume the taxpayer does NOT wish to contribute to the Presidential Election Fund, unless otherwise stated in
insens350 [35]

Answer:

Chapter 9 TRP 9-1

Assume the taxpayer does NOT wish to contribute to the Presidential Election Fund, unless otherwise stated in the problem.

 

Assume all taxpayers did NOT receive, sell, send, exchange, or otherwise acquire any financial interest in any virtual currency during the year.

 

Juliette White is a head of household taxpayer with a daughter named Sabrina. They live at 1009 Olinda Terrace, Apartment 5B, Reno, NV 78887. Juliette works at a local law firm, Law Offices of Dane Gray, and attends school in the evenings at Reno Community College (RCC). She is taking some general classes and is not sure what degree she wants to pursue yet. She is taking three units this semester. Full-time status at RCC is nine units. Juliette’s mother watches Sabrina after school and in the evenings (no charge) so that Juliette can work and take classes at RCC. Social security numbers are 412-34-5670 for Juliette and 412-34-5672 for Sabrina. Their birth dates are as follows: Juliette, 10/31/1988; and Sabrina, 3/1/2013.

The Form W-2 Juliette received from the Law Offices of Dane Gray contained the following information:

 

Wages (box 1) = $ 29,502.30

Federal W/H (box 2) = $ 1,007.14

Social security wages (box 3) = $ 29,502.30

Social security W/H (box 4) = $ 1,829.14

Medicare wages (box 5) = $ 29,502.30

Medicare W/H (box 6) = $ 427.78

 

Juliette also had the following expenses:

Education expenses:  

Tuition for Reno Community College $ 775

 

Prepare Juliette’s federal tax return. Use Form 1040 and any additional appropriate schedules or forms she may need for credits. For any missing information, make reasonable assumptions. (Input all the values as positive numbers. Instructions can be found on certain cells within the forms. Round your final answers to the nearest whole dollar amount. Do not skip rows, while entering in Dependents section of Form 1040 PG1.)

 

Use the appropriate Tax Tables and EIC table.

 

rev: 03_17_2021_QC_CS-257838

Step-by-step explanation:

4 0
2 years ago
Solve for y.
MariettaO [177]
5y = 135....divide both sides by 5
y = 135 / 5
y = 27 <==
7 0
3 years ago
Read 2 more answers
3. Tmobile charges 100 dollars for the initial phone line and then 20 dollars for every phone line afterwards.
salantis [7]
A)your equation for t-mobile would be
y=20x+100

Topar equation
y=30x

B) you’d set the two equation equal to each other

20x+100=30x

giving you the answer x=10

C) when x>13

D) when x<14

i’m a bit iffy on the last two but that’s the conclusion i came to

5 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
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