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3 years ago

I’m not sure what I’m doing here done everything they say to do but I keep getting it wrong pls explain

Mathematics

1 answer:

Marysya12 [62]3 years ago

3 0

Answer:

I'm pretty sure the peremiter is 466 ft.

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Angie baked 100 cookies and 20 brownies . she wants to split them into equal groups for the bake sale . each group must have the

Rainbow [258]

I would say for every 1 brownie, there are 5 cookies.

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3 years ago

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5/9 power -2 * 3/5 power -3 * 3/5 power 0

zavuch27 [327]

Answer:

Step-by-step explanation:

5/9^-2 = 81/25

3/5^-3 = 125/27

3/5^0 = 1

81/25 x 512/27 x 1 = 15

3 0

2 years ago

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Amy was scheduled for 12 intervals this week. One her first interval, she had a technical issue that prevented her from working

ad-work [718]

Based on the total of intervals vs the number of intervals Amy attended her CA percentage is 75%

<h3>What is the CA percentage?</h3>

The CA percentage measures the commitment of an employee to be logged in during the intervals that were assigned to him/her to work.

In this way, the CA percentage is equal to 100% if the employee worked as scheduled. Moreover, this percentage can be affected by factors such as:

Technical issues.
Human errors.

In the case of Amy, there is a total of 12 intervals and it is known:

She had a technical issue that prevented her from working, but this was reported so it is unlikely this is considered in her CA.
She missed three intervals because she looked at her schedule wrong.

Based on this information, let's calculate her CA:

12 intervals = 100%
9 intervals = x

x = 9 x 100 / 12
x = 900 / 12
x = 75%

Learn more about percentage in: brainly.com/question/8011401

6 0

3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago

I need help please, I am struggling

Juliette [100K]

Answer:

Step-by-step explanation:

5 0

3 years ago