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3 years ago

PLEASE HELP QUICK! I AM OFFERING 10 POINTS (Its only worth 4) AND BRAINLIEST ANSWER

Mathematics

1 answer:

Svetach [21]3 years ago

5 0

Answer:

1. (X+7)(x-4)

2. (2x-5)^2

3. 2(x+2)(x-2)

Step-by-step explanation:

There you go

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7 1/4 boxes weigh total of 66 7/8 what does one box weigh

Ray Of Light [21]

Answer:

68.875 / 7.25 = 9 1/2 pounds

Step-by-step explanation:

6 0

3 years ago

An airplane ascended into the sky to a steady altitude of 35000 feet. The same plane descended to a steady altitude of 32000 fee

love history [14]

Answer:

3000 feets

Step-by-step explanation:

Given that :

Initial Ascent to steady altitude = 35,000 feets

Descent to steady altitude = 32,000 feets

Number of feets the plane descend :

(Initial ascent to steady altitude - descent to steady altitude)

(35000 - 32000) feets = 3,000 feets

6 0

3 years ago

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST

AysviL [449]

Answer:

Step-by-step explanation:

The first choice is correct

The rate is 20 per dog, thus we get the equation:

c= 20d

However the first dog is free, so the equation becomes

c = 20(d - 1)

And he also has a walking fee of 85 dollars and thus the equation becomes

c= 85 + 20(d-1)

5 0

2 years ago

When 3 is subtracted from one third of a number n, the result is less than 6. Which inequality and solution represent this situa

MArishka [77]

Answer:

1/3n-3÷6

Step-by-step explanation:

3 is subtraced form 1/3

3 0

3 years ago

Read 2 more answers

Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths

Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e $(base)^2 + (Height)^2 = (Hypotenuse)^2$

For the given Lengths 7, 40 and 41

We need to check if

$7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2$

$Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681$

That means, $\\ 7^2 + 40^2 \neq 41^2$

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

$12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2$

Therefore given sides 12,16 and 20 can be the sides of right triangle.

7 0

3 years ago