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Sever21 [200]
3 years ago
12

Which system is most easily solved by graphing and why?

Mathematics
1 answer:
inn [45]3 years ago
8 0

Answer:

System A should be solved by elimination because you can easily cancel out the 3m to solve.

System B should be solved by substitution.  Since the an equation for the y value is given, you can easily substitute it into the other equation.

System C should be solved by graphing.  You don't have to worry about any slopes or intercepts to graph.  You can graph it using only whole numbers.

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12v+14+10v=80 combine Like terms again
sammy [17]
Well 12v and 10v are like terms so combine them.
 22v+14=80
If you are trying to solve the full equation it would look something like this:
22v+14=80
22v=56
<u>22v=56</u>
     22
v=2.54
4 0
3 years ago
Read 2 more answers
Help plssssss!!! (((:
katrin2010 [14]

Answer:

AB = 4.41

Step-by-step explanation:

cos theta = opposite / hypotenuse

We know theta = 25 and the opposite side =4

cos 25 = 4 / hypotenuse

Multiply each side by hypotenuse

hypotenuse * cos 25 = 4/ hypotenuse * hypotenuse

hypotenuse * cos 25 = 4

Divide each side  by cos 25

hypotenuse * cos 25/ cos 25 = 4/cos 25

hypotenuse = 4/cos 25

hypotenuse = 4.413511676

Round to the nearest hundredth

hypotenuse = 4.41

6 0
3 years ago
A car dealership offers customers two pricing options for vehicle repair. Option 1: pay $80 per hour of wok. Option 2: pay a sta
Ierofanga [76]

Answer:

1: The initial value for option one is not charged

The rate of change for option 1 is $80/hr

Step-by-step explanation:

1. From the pricing options at the car dealership we have;

Option 1

Initial value = Not stated

Fee rate per hour of work = $80

Option 2

Standard fee = $100

Fee rate per hour of work = $400

The initial value for option one is not charged

The rate of change = The increase in payment for each increase in one hour of work = $80/hour

Mathematically, we have;

The \ rate  \ of  \ change = \dfrac{\Delta Payment}{\Delta Time} = \dfrac{\$80 - \$0}{1 \, h- 0 \, h} = \$ 80/hr

5 0
3 years ago
For his phone service, Ivan pays a monthly fee of $14, and he pays an additional $0.05 per minute of use. The least he has been
Tomtit [17]

Answer:

1215 minutes are the possible numbers he has used his phone in a month.

Step-by-step explanation:

He has a monthly fee of 14$ then to the least that he has been charged we need to substract the monthly fee as follows:

Monthly charged = 74,75-14

Monthly charged= 60,75$

Then he pays an additional 0,05 $/minute of use, to know the consume:

Minutes= \frac{60,75}{0,05}

Minutes= 1215 possible numbers of minutes he has used his phone.

8 0
4 years ago
How to solve a problem.
mash [69]

a) \log \left(\dfrac{A^3B}{C} \right) = 3\log A + \log B - \log C

b) \log \left(\dfrac{\sqrt{A}}{B^2} \right) = \frac{1}{2}\log A - 2\log B

8 0
3 years ago
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