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3 years ago

Which system is most easily solved by graphing and why?

Mathematics

1 answer:

inn [45]3 years ago

8 0

Answer:

System A should be solved by elimination because you can easily cancel out the 3m to solve.

System B should be solved by substitution. Since the an equation for the y value is given, you can easily substitute it into the other equation.

System C should be solved by graphing. You don't have to worry about any slopes or intercepts to graph. You can graph it using only whole numbers.

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What is typically used to quantitatively compare the effectiveness of layouts? A. trial and error B. load-distance model C. expo

Andre45 [30]

Answer:

B. load-distance model

Step-by-step explanation:

A. trial and error

Trial and error is "a fundamental method of problem solving. It is characterised by repeated, varied attempts which are continued until success". But this method is not the best in order to compare effectiveness of layouts

B. load-distance model

The load-distance method is a "mathematical model used to evaluate locations based on proximity factors. The objective is to select a location that minimizes the total weighted loads moving into and out of the facility. The distance between two points is expressed by assigning the points to grid coordinates on a map". And that's the correct option since we are trying to measure the effectiveness of layouts quantitatively.

C. exponential smoothing

This is "a rule of thumb technique for smoothing time series data using the exponential window function". Wheighting observations using the exponential function. But this is a techinique used to smooth s time series not to compare effectiveness of layouts.

D.process control charts

The Control Chart is a "graph used to study how a process changes over time with data plotted in time order". But we don't want to see how the process changes the objective is quantitatively compare the effectiveness of layouts, and this one is not the best option for this.

E. mean absolute deviation (MAD)

The median absolute deviation(MAD) is "a robust measure of how spread out a set of data is. The variance and standard deviation are also measures of spread, but they are more affected by extremely high or extremely low values and non normality". But again is just a measure of spread and not allow to compare effectiveness of layouts.

8 0

3 years ago

Plz help ASAP

anygoal [31]

Answer:

B.40

Step-by-step explanation:

4 0

3 years ago

Why can't 1.07 pounds of sugar be compared to 1.23 cups of sugar?

Anuta_ua [19.1K]

Answer:

A pound is a measure of weight and a cup is a measure of volume.

Step-by-step explanation:

5 0

3 years ago

How do you use distributive property on s+0.08s?

Ivanshal [37]

Answer:

s(1+.08)

Step-by-step explanation:

Each term is divisible by s, so that means we can divide them by s, which we get 1+.08, therefore getting s(1+.08) (or s(1.08)).

7 0

3 years ago

Read 2 more answers

9.01 prove that the two circles are similar

il63 [147K]

Answer:

see the procedure

Step-by-step explanation:

we know that

Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.

In this problem to prove circle C and circle A are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that

Circle C is centered at (0,-1) and has a radius of 2 units

Circle A is centered at (3,4) and has a radius of 5 units

step 1

Move the center of the circle C onto the center of the circle A

the transformation has the following rule

(x,y)--------> (x+3,y+5)

(0,-1)------> (0+3,-1+5)-----> (3,4)

center circle C is now equal to center circle A

The circles are now concentric (they have the same center)

step 2

A dilation is needed to increase the size of circle C to coincide with circle A

scale factor=radius circle A/radius circle C-----> 5/2=2.5

radius circle C will be=2*scale factor-----> 2*2.5=5 units

radius circle C is now equal to radius circle A

therefore

A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

4 0

3 years ago