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nadya68 [22]
3 years ago
5

What is 15/20 simplest form

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0

Answer:

the simplest form of 15/20 is 3/4

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A jeweler wants to minimize business costs and has found that the average cost in dollars per necklace is given by C(x)=0.5x^2-7
Vika [28.1K]

Answer:

The maximum cost is 41 dollars per necklace.

Step-by-step explanation:

The average cost in dollars/necklace is given by :

C(x)=0.5x^2-7x+65.5  .....(1)

Where

x is the number of necklaces that are created

To maximize the cost, find the value of x by putting dC/dx = 0

\dfrac{d}{dx}(0.5x^2-7x+65.5)=0\\\\x-7=0\\\\x=7

Now put the value of x = 7 in equation (1).

C(x)=0.5(7)^2-7(7)+65.5\\\\=41\ \text{dollars per necklace}

Hence, the maximum cost is 41 dollars per necklace.

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3 years ago
When is the mean most useful in describing a set of data?
melamori03 [73]
The range is wide is the correct answer
4 0
3 years ago
Read 2 more answers
Write the following inequality using interval notation
mr_godi [17]
I think the answer is (9,8)
3 0
3 years ago
If 3/4 of an inch of rain fell in 1/2 hour, explain how to get the unit rate
bearhunter [10]

Answer:

Search to find the detailed rainfall collections if you want more detailed rainfall intensity data. If all available is monthly average in mm, take the monthly average and divide by number of hours in that month. So if you had 300 mm in April, take 360 mm/(30 days * 24 hours) = 0.5 mm/hour average monthly intensity. so that's it

4 0
3 years ago
The air force reports that the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a
Anon25 [30]

Answer:

Step-by-step explanation:

<em>Given that X -  the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>

<em />

<em>Height of male pilot = 74.2 inches</em>

<em />

<em>We have to find the percentile</em>

<em />

<em>X = 74.2</em>

<em />

<em>Corresponding Z score = 74.2-72.6 = 1.6</em>

<em />

<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>

<em />

<em>i.e. only 5% are below him in height.</em>

<em />

<em>Thus the malepilot is in 5th percentile.</em>

4 0
3 years ago
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