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asambeis [7]
3 years ago
9

Help me this is a trick question for me

Mathematics
2 answers:
joja [24]3 years ago
4 0

Answer:

what is the question and i will help you? did u add a picture or something bc i cant see anything except the question u asked

Step-by-step explanation:


yawa3891 [41]3 years ago
3 0

Answer:

<em>A. Yes, because 8^2 + 15^2 = 17^2</em>

Step-by-step explanation:

In a right triangle, the hypotenuse is always longer than the other two sides.

The longest side in this triangle is 17. If this is a right triangle, then the legs are 8 and 15, and the hypotenuse is 17.

We use Pythagoras theorem

(one leg)^2 + (other leg)^2 = (hypotenuse)^2

8^2 + 15^2 = 17^2

If the equation above is true, then it is a right triangle. If it is not true, then the triangle is not a right triangle.

8^2 = 64

15^2 = 225

8^2 + 15^2 = 64 + 225 = 289

17^2 = 289

From 8^2 + 64^2 = 17^2, we get

289 = 289

Since the equation is true, it is a right triangle.

Answer: A. Yes, because 8^2 + 15^2 = 17^2

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6 - y = 12 is what lol
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=−6

Step-by-step explanation:

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\left\{\begin{array}{ccc}x+3y-z=2\\4x+2y+5z=1\\3x+z=12&\to z=12-3x\end{array}\right\\\\\text{substitute the value of z to the first and second equation}\\\\\left\{\begin{array}{ccc}x+3y-(12-3x)=2\\4x+2y+5(12-3x)=1\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y-12+3x=2&|+12\\4x+2y+60-15x=1&|-60\end{array}\right\\\\\left\{\begin{array}{ccc}4x+3y=14&|\cdot2\\-11x+2y=-59&|\cdot(-3)\end{array}\right

\underline{+\left\{\begin{array}{ccc}8x+6y=28\\33x-6y=177\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ \ \ 41x=205\ \ \ \ |:41\\.\ \ \ \ \ \ \ x=5\\\\\text{substitute the value of x to the first equation}\\\\4(5)+3y=14\\20+3y=14\ \ \ \ |-20\\3y=-6\ \ \ \ \ |:3\\y=-2\\\\\text{substitute the value of x to the equation:}\ z=12-3x\\\\z=12-3(5)=12-15=-3\\\\x=5,\ y=-2,\ z=-3\to(5,\ -2,\ -3)

6 0
3 years ago
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