What should your units on your base area calculations be, and why? how is this different from the units on your volume calculati
1 answer:
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Answer:
See below for the graph.
Step-by-step explanation:
A circle or ellipse can be defined using the same sort of equation. Here, we have chosen to use the formulation ...
... ((x -a)/p)^2 +((y -b)/q)^2 -1 = 0
This will be the general form of the equation for an ellipse with center (a, b) and semi-axes p and q, in the x- and y-directions, respectively. When the axes are the same length, the ellipse is a circle.
By defining the function ...
... c(a, b, p, q, x, y) = ((x -a)/p)^2 +((y -b)/q)^2 -1
we can use the same function for all of the circles/ellipses in the figure. The parabola has vertex (0, -6) and a vertical scale factor of -1, so it can be formulated using the vertex form:
... y = k(x -a)^2 +b . . . . . for vertex (a, b) and vertical scale factor k.
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<em>The equations</em>
- (x/6)² +(y/6) -1 = 0
- (x+2)² +(y-2)² -1 = 0
- (x-2)² +(y-2)² -1 = 0
- (x/3)² +(y+2)² -1 = 0
- y = -x² -6
