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3 years ago

May someone please help me

Mathematics

1 answer:

swat323 years ago

3 0

5 - part to part

6- part to part

7- part to whole

8- whole to part

9- part to part

10-part to part

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3 years ago

What is the area of the triangle?<br> 2<br> 3<br> 6

nexus9112 [7]

Answer:

Step-by-step explanation:

2*3*6=12

12/2=6

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3 years ago

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The freezing point of water is 0 degrees Celsius or 32 degrees Fahrenheit. The boiling point of water is 100 degrees Celsius or

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3 years ago

Answer the question to become the brainliest

olya-2409 [2.1K]

Answer:

a) The distance travelled on the cycle in the first 14 seconds is 96 meters.

b) The acceleration in the first 4 seconds is 2 meters per square second.

Step-by-step explanation:

a) The distance travelled by the cycle is equal to the area below the curve, which is the sum of the first triangle and the rectangle:

$\Delta x = \frac{1}{2}\cdot \left(8\,\frac{m}{s} \right) \cdot (4\,s-0\,s)+\left(8\,\frac{m}{s}\right)\cdot (14\,s-4\,s)$

$\Delta x = 16\,m +80\,m$

$\Delta x = 96\,m$

The distance travelled on the cycle in the first 14 seconds is 96 meters.

b) The acceleration is represented by the slope of the line, which is determined by definition of secant line:

$a = \frac{v(4\,s)-v(0\,s)}{4\,s-0\,s}$ (1)

$a = \frac{8\,\frac{m}{s}-0\,\frac{m}{s}}{4\,s-0\,s}$

$a =2\,\frac{m}{s^{2}}$

The acceleration in the first 4 seconds is 2 meters per square second.

7 0

3 years ago

Suppose that $p$ and $q$ are positive numbers for which \[\log_9 p = \log_{12} q = \log_{16} (p + q).\] what is the value of $q/

SVEN [57.7K]

Given $p,q>0$ and $\log_9p=\log_{12}q=\log_{16}(p+q)=x$ (say).

Then,

$p=9^x\\ q=12^x\\ p+q=16^x$

From the above 3 equations,

$\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\$

From the equations, we get

$\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}$

Since $p,q>0$ , the negative value is rejected.

$\frac{q}{p}=\frac{1 + \sqrt{5}}{2}$

3 0

4 years ago