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2 years ago

What is the value of h? h = 20 h = 35 h= 55 h = 70

Mathematics

1 answer:

AlladinOne [14]2 years ago

7 0

Step-by-step explanation:

h=55

If you need a explaination message me on the comments

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Mr. Smythe needs gas for his car. If he spends $81 for 27 gallons, how much did he pay per gallon?

eimsori [14]

$3 dollars per gallon

6 0

2 years ago

Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

3 0

3 years ago

5(-7)+9(4) I am confused on this problem

amm1812

Answer:

the answer is 1

Step-by-step explanation:

5 0

3 years ago

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Without graphing, is the system independent, dependent, inconsistent? {12x=3y=12 y=-4x+5

Alla [95]

Okay so you out them into the form of y=mx+b. since equation 2 is already like that you need to do it to equation 1. which is y=-4x+4. graph both equations. if it has a solution (1 point where the two lines meet) it is consistantly and independent. if they are parallel lines and the solution is 0 the system is inconsistent and the lines are dependent. if it's the same line they are consistent and dependent. the line is not the same since the y intercept is different. the slope is the same though which tells us its parallel. so the system has a solution of 0 and is inconsistent and the lines are independent.

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3 years ago

K + 22 = 29 Solve the equation.

IceJOKER [234]

Look at the attached picture⤴

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3 years ago

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