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sp2606 [1]
3 years ago
10

You mow 3 lawns in 5 hours. How long will it take to mow 9 lawns? Explain your thinking​

Mathematics
1 answer:
Korolek [52]3 years ago
5 0
It will take 15 hours to mow 9 lawns
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What’s 11 + 9/35 make sure answer is a mixed number
mr_godi [17]

Answer: 11 9/35

Step-by-step explanation: just add the whole number to the fraction.

7 0
3 years ago
Read 2 more answers
-1/2(x-6)-1/4(x-4)=x-7
pentagon [3]
 -1/2(x-6)-1/4(x-4)-(x-7)= ?

Simplify 1/4
1 ÷ 4 = 0.25

Simplify 1/2
1÷2 = 0.5

The lowest common denominator of this problem is 4

16 - 3(x) / 4 - ( x - 7)

44 - 7(x) / 4

   -7(x)+44 = 0 

-7 - 44 = -51

-7 - 0 = -7

-7(x) = 44

-7(-1)(x) = x

-1(44) = -44

44 ÷ 7 = 6.28

We have have one solution in this problem

So, therefore x = 44/7
8 0
3 years ago
I WILL GIVE BRAINLIEST HELP PLEASEEEE HELP PLEASEEE
Lady bird [3.3K]

Answer:

-39

Step-by-step explanation:

\left(-3\right)^3-\sqrt[3]{27}-4^3\left(\sqrt[3]{64}-\left(2\right)\left(2\right)\right)-\frac{\left(3\right)^3\left(2\right)}{6}

-27-3-64\left(4-4\right)-\frac{54}{6}

-27-3-\frac{54}{6}

-27-3-9

Which gives us -39.

5 0
3 years ago
Find the area bounded by the curve y = x 1/2 + 2, the x-axis, and the lines x = 1 and x = 4 A. 16 B. 10 2/3 C. 7 1/2 D. 28 1/2
jeka94
To find the area of the curve subject to these constraints, we must take the integral of y = x ^ (1/2) + 2 from x=1 to x=4
Take the antiderivative: Remember that this what the original function would be if our derivative was x^(1/2) + 2 
antiderivative (x ^(1/2) + 2) =  (2/3) x^(3/2) + 2x
* To check that this is correct, take the derivative of our anti-derivative and make sure it equals x^(1/2) + 2

To find integral from 1 to 4:
Find anti-derivative at x=4, and subtract from the anti-derivative at x=1
2/3 * 4 ^ (3/2) + 2(4) - (2/3) *1 - 2*1
2/3 (8) + 8 - 2/3 - 2                               Collect like terms
2/3 (7) + 6                                             Express 6 in terms of 2/3
2/3 (7) + 2/3 (9)
2/3 (16) = 32/3 = 10 2/3          Answer is B

6 0
3 years ago
How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?
SCORPION-xisa [38]

Answer:

  • The value of   \log_2 100   is about 4 times the value of    \log_6 20

Explanation:

<u>1. Change of base rule</u>

       \log_ab=\dfrac{\log_{10}b}{\log_{10}a}=\dfrac{\log b}{\log a}

<u>2. Apply change of base rule to each of the given logarithm</u>

       \log_2 100=\dfrac{\log 100}{\log 2}\approx 6.64

       \log_6 20=\dfrac{\log 20}{\log 6}\approx 1.67

<u>3.Compare</u>

          \dfrac{6.64}{1.67}\approx 3.97\approx 4

<u>4. Conclusion</u>

The value   \log_2 100   is about 4 times the value of   \log_6 20

3 0
3 years ago
Read 2 more answers
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