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Serggg [28]
2 years ago
9

ANSWER ASAP TODAY FOR BRAINLIEST.

Mathematics
1 answer:
ivann1987 [24]2 years ago
5 0

Answer:

<em>Consistent independent</em>

<em>Consistent dependent</em>

<em>Inconsistent</em>

Step-by-step explanation:

<u>Consistent and Inconsistent Linear Systems</u>

A system of equations is consistent if it has at least one solution. If the solution is unique, then the system is consistent independent, otherwise is consistent dependent, i.e., it has an infinite number of solutions.

When there is no solution for the system, the lines of each equation are parallel but not coincident. A consistent dependent has two non-parallel lines, and a consistent independent system has only one line, i.e. the same line represents both equations.

Two lines are parallel if they have the same slope. To find the slopes, we represent the equations in slope-intercept form:

y = mx + b

Where m is the slope and b is the y-intercept.

Consider the system:

4x + y   = 8

x  + 3y = 8

Rearranging both equations:

y = -4x + 8

y = -1/3 x + 8

The slopes of the lines are -4 and -1/3 respectively, since they are different, the system is consistent independent.

Consider the system:

-4x + 6y = -2

2x - 3y = 1

Rearranging both equations:

y = 4/6 x - 2/6 = 2/3 x - 1/3

y = 2/3 x - 1/3

Both equations are exactly the same, thus the system is consistent dependent.

Consider the system:

5x - 2y = 4

5x - 2y = 6

Rearranging both equations:

y = 5/2 x - 2

y = 5/2 x - 3

These lines are parallel but not coincident. Thus this system is inconsistent.

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Please help me with this!!
Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the x values in the table. In other words, we need to replace x with each value in our given function and simplify.

- For x = 0

f(x)=(x-2)^2-5

f(0)=(0-2)^2-5

f(0)=(-2)^2-5

f(0)=4-5

f(x)=-1

Since x=0 and y=-1, our first point is (0, -1)

- For x = 1

f(x)=(x-2)^2-5

f(1)=(1-2)^2-5

f(1)=(-1)^2-5

f(1)=1-5

f(x)=-4

Our second point is (1, -4)

- For x = 2

f(x)=(x-2)^2-5

f(2)=(2-2)^2-5

f(2)=(0)^2-5

f(x)=-5

Our third point is (2, -5)

- For x = 3

f(x)=(x-2)^2-5

f(3)=(3-2)^2-5

f(3)=(1)^2-5

f(3)=1-5

f(x)=-4

Our fourth point is (3, -4)

- For x = 4

f(x)=(x-2)^2-5

f(4)=(4-2)^2-5

f(4)=(2)^2-5

f(4)=4-5

f(x)=-1

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

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Answer:

I used the answer the other person gave, but it said it was wrong. Here was the answer I put in the second time.

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