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3 years ago

Chandra and her friends bought three tubs of popcorn at the movies for t

Mathematics

2 answers:

zimovet [89]3 years ago

8 0

I believe the answer should be D hope it helped

lana [24]3 years ago

6 0

I think it’s D.3t-7-28 I hope I helped!

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Sara receives a 9% commission on every car she sells. The car dealership paid $20,000 for a car from an auction. The next day th

Paladinen [302]

Hey there! Your answer to this problem is 2160..

Explanantion:

Since every car Sara sells, she gets 9% of the commission, this means that at the last few step, we would have to give 9% of the total cost to Sara.

If 100% is 20,000, then 50% would be 10,000. But we have to find the cost of 20%. So what we would actually be doing is multiplying 20 with 0.01. 20x0.01 is 0.2 or 0.20.

Then you add the 4,000 to the 20,000 because it states, “the next day, they sold the car 20% more than they paid. This means that you’ll have to add it. 20,000 plus 4000 would be 24,000. So 24,000 would be the cost of the car they sold.

However they didn’t wanna know the cost of the car, they wanted to know how much Sara would get. So you would have to take 9% of the cost of the cost which would be 2,160.

Final result: $2,160

4 0

3 years ago

Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

3 years ago

The volume of a cube related to the area of a face by the formula V =A^3/2. What is the volume of a cube whose face has an area

11111nata11111 [884]

Answer:

Volume = 125 mm^3

Step-by-step explanation:

Here, we want to get the volume of the cube

What we have to do here is to substitute the value of the area

We have this as

V = 25^(3/2)

V = (√25)^3

V = 5 * 5 * 5 = 125 mm^3

6 0

3 years ago

Currently, the sum of the ages of Yumi, Rana and Victoria is 42 years. Four years ago, the sum of the ages of Rana and Victoria

Setler [38]

Y + R + V = 42
but 4 YEARS AGO : (R-4) +(V-4) = Y

Replace Y in the 1st equation by: (R-4) +(V-4)

(R-4) +(V-4) + R + V = 42

2R - 2V - 8 = 42; 2R -2V = 50, or R+V=25
IF R+V =25 AND Y + R +V = 42, then Y + 25 = 42 and Y =17

7 0

3 years ago

How do I write each number as a power of the given base? <br><br>example: 49; base 7

VLD [36.1K]

$7^n=49$
we know that 7*7=49 so thus $7^2=49$
$7^n=7^2$
therefor n=2
it is written as $7^2$

7 0

4 years ago