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IRINA_888 [86]
3 years ago
5

How do I find the ratio​

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0

Answer:

Ratios are like fractions. It is one part divided by the total amount of parts.

Step-by-step explanation:

for example there are 2 boys and 5 girls

so the ratio of boys to girls is 2:5

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PLLLEAAASSSEE HHEEELLLPPP!! :-))))
MariettaO [177]
Okay, well first look at the graph of the point "D". A translation from (7, -3) to (2, 5) is a movement of 8 units up, and 5 units left. So the conversion factor is (8, -5).

Now, I understand the points of the triangle are at (1, 4) (3, -2) and (4, 0). To reflect across the x-axis, to do this, merely flip the signs of the y-values of the coordinates.

A(1, 4) = A'(1, -4)
B(3, -2) = B' (3, 2)
C(4, 0) = C'(4, 0)

And that's all folks!
8 0
4 years ago
What is the least common multiple of 12 and 40?
Artyom0805 [142]

Answer:

120

Step-by-step explanation:


8 0
4 years ago
Read 2 more answers
Simplify the following expression. cot^2x secx-cosx
Solnce55 [7]

ANSWER

\cos(x)   \cot ^{2} (x)

EXPLANATION

The given expression is;

\cot^{2} (x)  \sec(x)  -  \cos(x)

Change everything to

\sin(x)

and

\cos(x)

This implies that,

\frac{ \cos^{2} (x) }{ \sin^{2} (x) }  \times ( \frac{1}{ \cos(x) } )-  \cos(x)

Cancel the common factors,

\frac{ \cos(x) }{ \sin^{2} (x) }  \times ( \frac{1}{1} )-  \cos(x)

\frac{ \cos(x) }{ \sin^{2} (x) }-  \cos(x)

\frac{ \cos(x)  -  \sin ^{2} (x)  \cos(x) }{ \sin^{2} (x) }

= \frac{ \cos(x)(1  -  \sin ^{2} (x) ) }{ \sin^{2} (x) }

= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }

= \cos(x)  \cot^{2} (x)

6 0
3 years ago
PLZ HELP ASAP GEOMETRY
zaharov [31]
I think the answer is 35
3 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7By%5E2%7D%7B36%7D%20-1" id="TexFormula1" title="\frac{y^2}{36} -1" alt="\frac{y^2}{36
liraira [26]

Answer:

that's my answer

Step-by-step explanation:

i hope it helps

5 0
3 years ago
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