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2 years ago

Answers: (0,12) (0,0) (cannot be determined) (6,0) Giving brainliest!

Mathematics

2 answers:

Nataly_w [17]2 years ago

5 0

Answer:

I would say the y-intercept is (0,0)

Step-by-step explanation:

finlep [7]2 years ago

4 0

(0,12) is the correct answer, I know this because the pattern for the table is when x decreases by one, f(x) increases by 2

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1 year ago

Which is the equation of the given line in slope-intercept form? (-1, 2) and (1, -4)

Natalka [10]

1. Find the slope using the slope formula.
$\frac{2 - ( - 4)}{ - 1 - 1} = \frac{2 + 4}{ - 2} = - \frac{6}{2} = - \frac{3}{1} = - 3$
2. Plug that slope and either point into an equation in slope-intercept form and solve for b.
$2 = - 3( - 1) + b \\ 2 = 3 + b \\ - 1 = b$
3. Now write your answer as a slope-intercept form equation
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3 years ago

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How many 2.5" x 6" tiles with it on the backsplash that was 2.5 feet tall and 8 feet long

Dahasolnce [82]

24 cause you can only fit 24 on a backsplah

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3 years ago

PLEASE SHOW FULL SOLUTIONS!!! WILL MARK BRAINLIEST!!! SHOW ALL STEPS!!! THANK YOU!!!

ELEN [110]

9514 1404 393

Answer:

a) BE = 5; DE = 6; EF = 4

b) ∠EFC ≅ ∠DA.F ≅ ∠BDE or <em>b = e = f = i</em>

Step-by-step explanation:

Each short segment is the same length as the marked one it is parallel to.

E is the midpoint of BC, so BE = EC = 5.

ADEF is a parallelogram, so DE = A.F = 6.

D is the midpoint of AB, so AD = DB = 4. ADEF is a parallelogram, so ...

EF = AD = 4

As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>

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2 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

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3 years ago