The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.
The second and third one are correct
Answer:
C
Step-by-step explanation:
C is the only viable answer, because it it the only one that decreases as x approaches infinity. Exponential decay decreases, hence the decay part.
I think that using the elimination method is the best, because it is the only method that I use when solving these types of equation. For example, for these two equations, you need to multiply one of the equations by a certain number so that you'd be able to find x and y. The elimination method is the method that tells you to do that. It is also the easiest method.
~Hope I helped!~
It is rational because any number that can be represented in a fraction is rational. 4/33 is a fraction, so it is rational.
