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In-s [12.5K]
3 years ago
6

Answers: (0,12) (0,0) (cannot be determined) (6,0) Giving brainliest!

Mathematics
2 answers:
Nataly_w [17]3 years ago
5 0

Answer:

I would say the y-intercept is (0,0)

Step-by-step explanation:

finlep [7]3 years ago
4 0
(0,12) is the correct answer, I know this because the pattern for the table is when x decreases by one, f(x) increases by 2
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PLEASE EXPALIN :))))) ( THERES A PIC)
Bond [772]
Altitudes make right angles so it is C
3 0
3 years ago
Please help , I would sincerely appreciate it
kozerog [31]

Answer:

B . S /2rh =pi

Step-by-step explanation:

S = 2* pi * r*h

We are solving for pi

Divide both sides by 2rh to isolate pi

S/ 2rh = 2 * pi *r* h / 2rh

S /2rh =pi

5 0
3 years ago
What is the area????
Ad libitum [116K]

Answer:

49.1 cm^2

Step-by-step explanation:

The appropriate area formula is ...

area = (1/2)(side 1)(side 2)(sin(angle between))

= (1/2)(10 cm)(12 cm)·sin(55°) = 60·sin(55°) cm^2

area ≈ 49.1 cm^2

6 0
3 years ago
Please help! thanks :)
Molodets [167]

Answer:

118%

Step-by-step explanation:

Cora's kitten weighed in the last visit to the veterinarian's office= 550 grams

Right now, Cora's kitten weighs = 1200 grams

Increase in the kitten's weight= 1200 - 550 = 650 grams

Percent increase in weight= 650/550 * 100

= 118.18% = 118%

Hence, there is 118% increase in kitten's weight.

7 0
3 years ago
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi
Margaret [11]

Answer:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=26Kg

Step-by-step explanation:

Data

Brine a (Ba)

V_{Ba}=5\frac{Lt}{min}\\  Concentration(Bca)=0.05\frac{Kg}{Lt}

Brine b (Bb)

V_{Bb}=10\frac{Lt}{min}\\  Concentration(Bcb)=0.04\frac{Kg}{Lt}

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}

Finally:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=0.65\frac{Kg}{min}(40min)=26Kg

being y(t) the amount of salt (y) per unit of time (t)

5 0
3 years ago
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