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Pavlova-9 [17]
3 years ago
13

Find the distance from (8,-2) to (8,-16)

Mathematics
1 answer:
raketka [301]3 years ago
6 0

Answer:

14

Step-by-step explanation:

- Square root of (x2-x1) squared + (y2-y1) squared

- which is square root of (8-8) squared + (-16-(-2)) squared

-simplify it, then get 14

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Which system of equations would have no solution? pls helpp
Leya [2.2K]

Answer:

3x+y=8 and 3x+y=9

Step-by-step explanation:

Assume these two equations:

a1x+b1y+c1=0

a2x+b2y+c2=0

If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.

In these case, take a look at the last option:

3x  + y = 8 \\ 3x + y = 9

Re-write 'em as a standard form:

3x  + y - 8 = 0 \\ 3x + y - 9 = 0

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

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Please help me
Kruka [31]

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

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x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

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now 2nd equation

y = 2x^2 + x

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x = -1

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x = 0

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y = 2(2)^2+2= 8 + 2 = 10

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Answer:

i dont get it

Step-by-step explanation:

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