Answer:
let x be the number then,
according to question ,
10+4x=73-3x
or, 4x+3x=73-10
or, 7x= 63
or, x= 63÷7
or,x=9 ans
hence , the number is 9
Answer:
x = 3/8 or 0.375
Step-by-step explanation:
For this equation, you need to set it up so it's easier to work with. For example, 3x + x - 3 ÷ 2 = 0. Next, use the order of operations which is the acronym PEMDAS.
P = parentheses (first if there is any)
E = exponents (if there is any)
M/D = Multiply or Divide
A/S = Add or Subtract
Since we have a division problem to do, we need to simplify the division first based on the order of operations.
3x + x <u>- 3 ÷ 2 </u>= 0. -3 ÷ 2 is equal to -1.5. Every division problem is also a fraction. Next, you will have left 3x + x - 1.5 = 0. When you have both subtraction and addition in the equation, all you have to do is solve from left to right. There is an addition problem to solve first then the subtraction problem. For example: <u>3x + x</u> - 1.5 = 0, which equals to 4x - 1.5 = 0. Next, you add 1.5 to -1.5 and 0. Anything added or subtracted by a number and it's opposite will always equal 0. For example: 4x <u>- 1.5 + 1.5</u> =<u> 0 + 1.5. </u> You have to get rid of the -1.5 and 1.5 since it equals 0. This will be left with 4x = 1.5. Divide both sides by 4 to balance the equation. For example: <u>4x ÷ 4 = 1.5 ÷ 4. </u>Do you see that the 4's on one side cancel each other out? You are left with x = 3/8.
Answer:
double, real root x = -4
Step-by-step explanation:
Please use " ^ " to indicate exponentation: 2х^2 + 8х = х^2 - 16.
Combine like terms:
х^2 + 8х = - 16.
Re-write in the standard form for a quadratic:
х^2 + 8х + 16 = 0
Recognize that this is the square of the binomial x + 4:
х^2 + 8х + 16 = 0 => (x + 4)^2 = 0
Solving this last result for x yields the double, real root x = -4.
Option cC , BC =QR for SSS
The correct answers are:
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[A]: " (0, 0) " ; <u>AND</u>:
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[C]: " (-2, -1) " .
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Explanation:
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[A]: " (0, 0) " ; is correct;
Since, when "x = 0" and y = 0 :
"0 <span> > - 4 " ; which is correct.
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[B]: "(2, 1)" is incorrect, since:
when "x = 2" and "y = 1" ;
" 1 > 6" ; is incorrect.
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[C]: "(-2, -1)" ; is correct;
Since, when "x = -2" and y = -1" ; then:
"-2 <span> > -6 ; which is correct.
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[D]: " (-5, -1) " ; is INCORRECT.
since when "x = -5" and "y = -1 ;
then: -1 > 6 ; which is INCORRECT.
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