Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
No they do not form a right triangle
1.=(2/3,0) 2.=(-3,0) 3.=-10 4.=need a graphing calc 5.=need a graphing calc
Answer:
angle 1 and angle 3 are congruent
Step-by-step explanation:
Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.
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If you like, you can get there algebraically:
m∠1 + m∠2 = 180
m∠3 + m∠2 = 180
Subtract the second equation from the first:
(m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)
m∠1 -m∠3 = 0 . . . . simplify
m∠1 = m∠3 . . . . . . add m∠3
When angle measures are the same, the angles are congruent.
∠1 ≅ ∠3
I hope this helps you
answer is D
