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3 years ago

Find the volume of the sphere with a radius, r, of 3/2 feet and π ≈ 3.14.

Mathematics

2 answers:

Mars2501 [29]3 years ago

7 0

V = 14.13

I answered another question like this one earlier ;)

nalin [4]3 years ago

3 0

Answer:

V= 14.13

Step-by-step explanation:

Information needed:

V= 4/3 $\pi$ r^3

$\pi$ = 3.14

r= 3/2

Solve:

V= 4/3 $\pi$ r^3

V= 4/3(3.14)(3/2)^3

V= 4/3(3.14)(27/8)

V= 14.13

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Ross needs to have a procedure done, and since he is over 65 he is on Medicare. Medicare says that according to their plan the a

Anni [7]

Answer:

$\large \boxed{\$1200.00}$

Step-by-step explanation:

Let the office charge = x

Amount paid by Medicare = ⅞x

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Check:

$\begin{array}{rcl}\dfrac{1}{4} \left(\dfrac{7}{8}\times \$1200.00 \right ) & = & \$262.50\\\\\dfrac{1}{4} \left(\$1050.00 \right ) & = & \$262.50\\\\\$262.50 & = & \$262.50\\\end{array}$

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3 years ago

Find the unknown G/20=0.65 0.7=7/W N/50=0.18

iren [92.7K]

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3 years ago

Read 2 more answers

A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume

mixer [17]

Answer:

(a) 0.4096

(b) 0.64

Step-by-step explanation:

The probability that the player wins is,

$P(W)=0.80$

Then the probability that the player losses is,

$P(L)=1-P(W)=1-0.80=0.20$

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = $P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096$

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = $1-P(L)-P(WL)$

$=1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64$

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let X = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable $X\sim Bin(n=3, p=0.4096)$

The probability distribution of binomial is:

$P(X=x)={n\choose x}p^{x} (1-p)^{n-x}$

The probability that the player defeats all the 4 opponents at least once is,

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942$

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0

3 years ago