Answer:
Step-by-step explanation:
1)
O = center of circle (origin)
we know that the angle at the center of the circle ∠ ROS will be
180= 2(31) + ∠x
180-62 = ∠x
118° = ∠x
The supplemental angle to the 118° will be 62°
62° is the interior angle to arc QR , so
arc QR is also 62°
3)
b/c the intercepted arc YZ = 2* 68=136
then 136+125+? = 360
? = 99°
arc ZX = 99°
5)
O= center point
we are given the two arcs 120 and 70 for both of these we know that the
interior angles will be the same. ∠JOX has a central angle of 120 , then
b/c triangle JOX is an isosceles, we know that the two angles J and X of
the triangle JOX will be 1/2 of 60 , or 30 each
also for
also ∠XOY has an interior angle of 70 so the two angle at X and Y will be 1/2 of 110 , or 55°
now add 55+30 to find X for box XYZJ
85° = ∠X
Answer:
444
Step-by-step explanation:
since 37/100 students liked chocolate you need to scale that data to the new data size and find thirty seven percent of 1200 which is 444
The answer should be 24 square units.
5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.
In order to do that, we need to use the Pythagorean Theorem.
a^2+b^2=c^2
3^2+b^2=5^2
9+b^2=25
Subtract 9 from both sides
b^2=16
Then square root both sides.
b=4.
Now that we have the base, you can then find the area of the triangle.
BH/2
4*3/2
12/2
6
So one triangle equals to 6. Then multiply that by 4 to find the area of the rhombus. Which would be 24 square units.
Answer:
Step-by-step explanation:
Since the box contains a cylinder, the height of the box must be gt; = cylinder height
And the area at the bottom of the box is definitely larger than the area at the bottom of the cylinder.
The area at the bottom of the cylinder is PI r squared,
If the bottom of the box is a square, then the area of the bottom is 4r^2, whereas the bottom tends to be polygon, which is equivalent to cutting the circle into equal parts by circle cutting.
So the area at the bottom of the box is 
，
It follows that the volume of the box is greater than the volume of the cylinder
The answer is a. 5. Good luck
