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Katyanochek1 [597]
3 years ago
7

Cross a person who does not have freckles and is heterozygous for dimples with a person who has

Biology
1 answer:
Alja [10]3 years ago
4 0

Answer:

1. 1/2

2. 1/2

3. 1/4

Explanation:

Let the allele for freckles be A or a while that of dimples be B or b.

A person without freckles but heterozygous for dimples = aaBb

A person who has freckles (whose mother has no freckles) but no dimples = Aabb

      aaBb    x    Aabb

Offspring

4 AaBb - freckled and dimpled

4 Aabb - freckled and non dimpled

4 aaBb - non freckled and dimpled

4 aabb - non freckled and non dimpled

1. <em>Probability that the parents will have a dimpled child</em> = 8/16 or 1/2

2. <em>Probability that they will have a child with freckles</em> = 8/16 or 1/2

3. <em>Probability that they will have a child with freckles and dimples</em> = 4/16 or 1/4

<u>See the attached image for the Punnet's square analysis of the cross</u>

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Answer:

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