Perimeter of quadrilateral ANCM = AN+NC+CM+MA
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in
Answer:
x=2
y=3
Step-by-step explanation:
Answer:
w = 3
Step-by-step explanation:
-6(w - 4) + 8W=6(w + 2)
-6w + 24 + 8w = 6w + 12
2w + 24 = 6w + 12
12 = 4w
3 = w
Answer:
2 3/5
Step-by-step explanation:
13/5
5 goes into 13 2 time
2*5 =10
13-10 =3
There is 3 left over. This goes over the denominator
2 3/5
Equation of a circle is:
<span>(x−h<span>)2</span>+(y−k<span>)2</span>=<span>r2</span></span>
h is the x-coordinate of the center and k is the y-coordinate of the center. Even though the formula has minus signs, those are positive numbers. If there were plus signs in there, the numbers h and k would actually be negative. Now since you're centered at the origin, that means h and k are 0, so you'd just have this:
<span><span>x2</span>+<span>y2</span>=<span>r2</span></span><span>
Now since your radius is 7, just square it and replace r^2 woth that value :)</span>
