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3 years ago

Given that a^b = x, evaluate the following: 2a^3b +a^2b+ a^b

Mathematics

1 answer:

Bingel [31]3 years ago

8 0

Answer:

2x^3+x^2 +x = x(2x^2 +x+1)

Step-by-step explanation:

a^b = x,

2a^3b +a^2b+ a^b=

2(a^b)^3+(a^b)^2 +a^b=

2x^3+x^2 +x=

x(2x^2 +x+1)

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3 years ago

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Answer:

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Step-by-step explanation:

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Subtract 5 on both sides:

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$\cos(\frac{1}{2}x)=\frac{2}{3}$

Now since $\cos(u)$ is even then $\cos(u)=\cos(-u)$ .

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3 years ago

Given that a^­­b = x, evaluate the following: 2a^3b +a^2b+ a^b

Given that a^b = x, evaluate the following: 2a^3b +a^2b+ a^b