Question

The answer isn't 8-2root3 btw

Answer 1

Answer:

Step-by-step explanation:

16cos(30)-20sin(60) -8sin(90)

look at the pattern of the numerators Millie, you can remember all of the sin and cos  functions at the special angles now. :)

sin(0) = 0 / 2

sin(30) = 1 / 2

sin(45) = $\sqrt{2}$ / 2

sin(60) = $\sqrt{3}$ / 2

sin(90) = $\sqrt{4}$ / 2   aka  1

now the numerators just count up from 90°

cos(90) = 0 / 2

cos(60) = 1 / 2

cos(45) = $\sqrt{2}$ / 2

cos(30) = $\sqrt{3}$ / 2

cos(0) =  $\sqrt{4}$ / 2   aka  1

see the pattern.. it's pretty easy to memorize, knowing that :)

now let's use the above to plug into the given equation

16* $\sqrt{3}$ / 2 - 20* $\sqrt{3}$ / 2- 8*$\sqrt{4}$ / 2

8* $\sqrt{3}$ - 10 $\sqrt{3}$  -8

-2*$\sqrt{3}$  - 8

this isn't quite the same answer as you got before.. I feel like it's right

Answer 2

Answer:

1.41226231144

Step-by-step explanation: