Can someone solve this equation and show the work please 8.3(x+3.1)=83

PLEASE HELP, LAST THING I NEED TO GRADUATE

Mice21 [21]

For a), wouldn't you multiply the cost of a twin by the quantity of a twin beige (N) and the cost of a queen by the quantity of the queen beige (N) and then the cost of the king by the quantity of the king beige (N) for CN and do the same thing but with the south quantities?
And then for b), it's just comparing which one had the most money and find the difference...
And then C), would be relatively self explanatory where CN would be the potential profit in N and CS would be the potential profit in S and then CN+CS would be the potential profit total?

7 0

3 years ago

Can someone please help me answer this??

rewona [7]

<h3>Answer: x = (y-2)^2 + 5</h3>

In other words, y-2 goes in the first box and 5 goes in the second box.

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Work Shown:

y^2 - 4y - x + 9 = 0

y^2 - 4y + 9 = x

x = y^2 - 4y + 9

x = y^2 - 4y + 4 + 5 .... rewrite 9 as 4+5

x = (y^2-4y+4) + 5

x = (y-2)^2 + 5 .... apply the perfect square factoring rule

So we'll have y-2 go in the first box and 5 goes in the second box

note: One version of the perfect square factoring rule says (a-b)^2 = a^2-2ab+b^2.

4 0

3 years ago

Read 2 more answers

Graph: y + 2= -3/4 ( x+4)

S_A_V [24]

Answer:

The slope is -3/4 y intercept is (0,-5)

Step-by-step explanation:

X Y

-20/3 0

0 5

graph ^

y + 2= -3/4 ( x+4)

6 0

3 years ago

Question 3<br> Describe the function between x=-4 and x = -1.

murzikaleks [220]

Answer:

liner increasing

Step-by-step explanation:

8 0

3 years ago

The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0

STatiana [176]

Answer:

The marginal-revenue equation is $R'(x)=0.1226x+1.1584$ .

The marginal revenue for the production of 200,000,000 bushels is $R'(x)=1.4036$ .

The marginal revenue for the production of 650,000,000 bushels is $R'(x)=9.1274$ .

Step-by-step explanation:

The derivative $R'(x)$ of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, $R(x) = 0.0613x^{2} +1.1584x+2.4813$ . Therefore, the marginal revenue function is

$R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584$

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036$

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274$

3 0

3 years ago