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Bingel [31]
3 years ago
9

14 POINTS PLEASE HELP

Mathematics
1 answer:
Anika [276]3 years ago
4 0

Answer:

5 cars and 3 busses

Step-by-step explanation:

You might be interested in
Calculate the area of his garden from the picture below pls help
MaRussiya [10]

Answer:

Hello! answer: 105.5

Hope that helps!

75 + 18 + 12.5 = 105.5

5 0
3 years ago
Can someone help me with this problem?
Sedbober [7]
<h3>Answer:  2(11+9)</h3>

Explanation:

22 = 2*11

18 = 2*9

We see that 2 is the GCF of 22 and 18. It's the largest shared factor.

Now use the distributive property to say the following

22 + 18

2*11 + 2*9

2(11+9)

To check the answer, multiply the outer 2 by each term inside to end up with 22+18 again.

3 0
3 years ago
Someone tell me What is 3/4 + 5/8
Charra [1.4K]

Answer:

1.375

Step-by-step explanation:

3/4 is 0.75,

5/8 is 0.625

so 0.75 + 0.625=1.375

3 0
3 years ago
Read 2 more answers
Plz, answer. Will mark brainiest. Please! 50 points!!!
igomit [66]

Answer:

12%

Step-by-step explanation:

874990                        874990

x 0.12       ----------->   -  104998

--------------                  -------------------

104998                         769991

Hope this helped!

3 0
3 years ago
Assume that 140 surveys are completed. Of those surveyed, 71 responded positively to effectiveness, 60 responded positively to s
liraira [26]

Answer:

15

Step-by-step explanation:

Let n(T) denotes total surveys done i.e. n(T)=140

Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71

Let n(B) be the no. of side effects i.e.n(B) =60

Let n(C) be the no. of responses to cost i.e. n(C)= 65

33 responded positively to both effectiveness and side effects

So, n(A∩B)=33

31 to effectiveness and cost

n(A∩C)=31

28 to side effects and cost

n(B∩C)=28

21 to none of the items

So, n(A∪B∪C)=140-21 = 119

we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)

Formula:

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)

119=71+60+65-33-31-28+ n(A∪B∪C)

119=104+ n(A∪B∪C)

119-104= n(A∪B∪C)

15= n(A∪B∪C)

Hence 15 responded positively to all three

7 0
3 years ago
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