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3 years ago

6

Amber needs to select six players for her volleyball team. there are 10 players to choose from. how many possible combinations o

f teams could amber choose?

1 answer:

Dima020 [189]3 years ago

8 0

Amber can make a possible number of 12 different teams

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In a two-digit number, the units digit is 5 more that the tenth digit. The number itself is three times the sum of its digits. W

postnew [5]

Answer:

15

Step-by-step explanation:

1+5=6

6*3=15

7 0

3 years ago

Read 2 more answers

How do you do number 2? Help please and thank you.

Dmitrij [34]

Answer:

{3,-1}

Step-by-step explanation:

m^2 -2m -3=0

What 2 numbers multiply to -3 and add to negative 2

-3* 1 = -3

-3 +1 =-2

(m-3) (m+1) =0

Using the zero product property

m-3 = 0 m+1 =0

m=3 m=-1

{3,-1}

6 0

4 years ago

The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

$(6,112,50), (11,206.25)$

$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

3 years ago

What is the half of 62

VashaNatasha [74]

The half of 62 = 62/2
= 31
:|

3 0

3 years ago

Read 2 more answers

A $250,000 home loan is used to purchase a house. The loan is for 30 years and has a 5.4% APR. Use the amortization formula to d

wlad13 [49]

$\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\
~~~~~~
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &250000\\
pymt=\textit{periodic payments}\\
r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{since the payments are}\\
\textit{monthly, then twelve}
\end{array}\to &12\\
t=years\to &30
\end{cases}
$

$\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right]
\\\\\\
pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right]
\\\\\\
pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right]$

8 0

3 years ago