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denis23 [38]
3 years ago
6

Amber needs to select six players for her volleyball team. there are 10 players to choose from. how many possible combinations o

f teams could amber choose?
Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
Amber can make a possible number of 12 different teams
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15/35 in simplest form
Aleksandr-060686 [28]
Find the GCF of 15 and 35
15=3*5
35=7*5
The Greatest Common Factor here is 5
Divide both the numerator and denominator by this value to get the simplest form.
15/5=3
35/5=7
Final answer: 3/7
5 0
4 years ago
Read 2 more answers
4x-10=30<br> 2n-7=30 <br> S/3+2=4
emmasim [6.3K]

Answer:

x=10 n=18.5 s=6

Step-by-step explanation:

4x-10=30

Add 10 to both sides

4x-10+10=30+10

4x=40

Divide by 4 on both sides

(4x)/4=40/4

x=10

2n-7=30

Add 7 to both sides

2n-7+7=30+7

2n=37

Divide by 2 on both sides

(2n)/2=37/2

n=18.5

(s/3)+2=4

Subtract 2 from both sides

(s/3)+2-2=4-2

(s/3)=2

Multiply by 3 on both sides

3s/3=2*3

s=6

6 0
4 years ago
The model builder has 4 pieces of balsa wood that are 4 cm, 5 cm, 6 cm, and 7 cm length. How many different combinations of 3 pi
s2008m [1.1K]
About 22 i think hope it helps in any way

7 0
3 years ago
A clothing company has 4 different kinds of sweatshirts. Each year, the company makes 60,000 of each kind of sweatshirt. How man
Anna007 [38]

Answer:

Step-by-step explanation:

Given that,

The company makes 4 different sweat shirts

Each year they make 60,000 of each kind.

So, if they will make 60,000 sweat shirt for each brand and the company design 4 different brand.

So, number of brand is 4

n = 4.

Then,

1 brand = 60,000

Therefore, 4 brand = 60,000 × 4

4brand = 240,000 sweat shirts.

So, in a year the company will make 240,000 sweat shirts.

4 0
3 years ago
PLEASE HELP ME I HAVING TROUBLE
viktelen [127]

Answer: f(-6) = -\frac{12}{11}, f(-4) = \frac{8}{9}, f(4) = -\frac{8}{9}, f(6) = \frac{12}{11}

<u>Step-by-step explanation:</u>

(-6, f(-6)) is an x,y coordinate.  They are asking what the y-value is when you plug in -6 for x.

f(x) = \frac{2x}{x^{2}-25}

f(-6) = \frac{2(-6)}{(-6)^{2}-25}

      = \frac{-12}{36-25}

      = -\frac{12}{11}

f(-4) = \frac{2(-4)}{(-4)^{2}-25}

      = \frac{-8}{16-25}

      = \frac{-8}{-9}

      = \frac{8}{9}

f(4) = \frac{2(4)}{(4)^{2}-25}

      = \frac{8}{16-25}

      = \frac{8}{-9}

      = -\frac{8}{9}

f(6) = \frac{2(6)}{(6)^{2}-25}

      = \frac{12}{36-25}

      = \frac{12}{11}

5 0
3 years ago
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