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Andrei [34K]
3 years ago
13

Helpppppp please asp

Mathematics
1 answer:
Ksju [112]3 years ago
7 0

I believe the answer is D: 6×9÷3.

The question is a word problem, and they are asking you to put it into a numerical problem, meaning with numbers. 6 times 9 divided by 3 put into a numerical equation is 6×9÷3.

<em>If this is incorrect, please, don't refrain to tell me. Thank you.</em>

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What is -8.64 -0.024?<br>360<br>- 36<br>-360<br>36​
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Step-by-step explanation:

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Read 2 more answers
The function g has an inverse. The function g − 1 determines the number of folds needed to give the folded paper a thickness of
Amanda [17]

Answer:

\mathbf{g^{-1} (t) = log _2  \ 20 \ t}

Step-by-step explanation:

Here is the full question

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.

Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

g(n )= (05)2^n

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).

<u>SOLUTION:</u>

If we represent g(n) with  t;

Then

\mathbf{t = (0.05)2^n} \\ \\ \mathbf{\dfrac{t}{0.05} = 2^n} \\ \\ \mathbf{\dfrac {100 \ t }{ 5} = 2^n} \\  \\ \mathbf{20 t = 2^n}

Taking logarithm of both sides; we have :

\mathbf{log (20 t) = n log 2}    \ \ \    \mathbf{(since  \ ,  log  \ a^b = b \ log \ a) }  \\ \\ \mathbf{n =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) = log _2  \ 20 \ t}

4 0
4 years ago
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