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kykrilka [37]
3 years ago
10

Pleaseeee help I need a answer fast

Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

300

Step-by-step explanation:

im smart

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Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
Evaluate x(y+3)/(3+y)z for x=12, y=1, and z=6.<br><br> A) 2<br><br> B) 5<br><br> C) 8<br><br> D) 6
fgiga [73]

Answer:

2

Step-by-step explanation:

We take the equation

x(y+3)/(3+y)z

and substitute the values for each individual variable in the problem. It looks like this:

12(1+3)/(3+1)6

Now we can solve the equation.

When solved, it equals 2.

5 0
3 years ago
Read 2 more answers
*HELP PLEASE*
aksik [14]
If two events are disjoint (i.e. mutually exclusive) they cannot both occur and so we can determine probabilties by simple addition:

P(AorB)=P(A)+P(B) 
P(AorB)=\frac{40}{61}+\frac{2}{61} 
P(AorB)=\frac{42}{61} 
P(AorB)\approx 68.8\% 

A more complete answer would use a joint probability table but that's difficult to type out/format correctly here. 
7 0
4 years ago
Answerr please<br> .........................
AlexFokin [52]

Answer: I think its the third choice. It's asking for the progress of the height.

8 0
4 years ago
Read 2 more answers
Did I do this right? If not please explain!
andrew11 [14]
Yep! Good job, you did it correctly.
Your y-intercept is equal to the constant of the equation (y-int = -2). Your movement/direction (or rise over run) is equal to the variable. Since your variable is x (which can also be written as 1x) means you move up one and over one (rise over run). This is because 1/1 is equal to 1.
5 0
3 years ago
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