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3 years ago

FASTEST WITH EXPLAINATION ANSWER GETS BRAINLIEST

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

Answer:

explanation to what

Step-by-step explanation:

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Price - $375<br> Discount - 20%<br> Total =

Yanka [14]

Answer: 20

Step-by-step explanation: since i helped can i have brainlist plesa :D

8 0

3 years ago

Justin and George bought some baked goods. Justin purchased 5 cookies for x dollars each and 4 doughnuts for y dollars each and

borishaifa [10]

The given statement 5x=4y=12 and x+6y=5 is true.

<u>Step-by-step explanation:</u>

The question comes from linear equations in two variables.

Here, two unknown variables represent a certain situation and their value can be obtained by solving both the given equations.

The cost of cookie is represented by the variable x and cost of doughnuts can be represented by the variable y.

The coefficient of each variable in the equation represent the quantity or the number of units of each baked good.

On comparing the given equations from the data provided in the question, the statement can be stated as true.

8 0

3 years ago

Read 2 more answers

Best way to tell someone no without being mean

m_a_m_a [10]

Answer:

Try to search up euphemisms to help you in an argument where your forced to say no

Step-by-step explanation: In this situation apologize to them and say

I can't do that or no

6 0

2 years ago

The quotient of a number and -7 decreased by 2 is 10 find the number

yarga [219]

X/-7 -2 =10
x/-7 = 12
x = -84

7 0

3 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago