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mamaluj [8]
2 years ago
5

Which shows the expressions rewritten with the least common denominator?

Mathematics
1 answer:
baherus [9]2 years ago
7 0

Answer:

  D.  (14x-4)/(8x^2) and (x^2-x)/(8x^2)

Step-by-step explanation:

The least common denominator will be 8x^2, the product of 2 and x to the highest of their powers in either of the denominators.

  \left\{\dfrac{7x-2}{4x^2},\ \dfrac{x-1}{8x}\right\}=\left\{\dfrac{7x-2}{4x^2}\cdot\dfrac{2}{2},\ \dfrac{x-1}{8x}\cdot\dfrac{x}{x}\right\}\\\\=\left\{\dfrac{14x-4}{8x^2},\ \dfrac{x^2-x}{8x^2}\right\}

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(1 - cosx) (1 + 1/cosx) = sinxtanx
Nataly [62]

Answer:

cos x ≠ 0 ⇔ x ≠ \frac{pi}{2}+k.pi ; k ∈ N

(1-cosx)(1+\frac{1}{cosx})=sinx.tanx\\\\(1-cosx)(\frac{cosx+1}{cosx})=sinx.\frac{sinx}{cosx}\\\\ \frac{1-cos^{2} x}{cosx} =\frac{sin^{2}x }{cosx}\\\\=>1-cos^{2}x=sin^{2}x

<=> cos²x + sin²x = 1

⇔ 1 = 1

=> x =  { R \ (pi/2 + k.pi); k ∈ N}

Step-by-step explanation:

5 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
coach increase the number of sit-ups in PE from 40 to 55 by what percent did Coach change the number of sit-ups required
konstantin123 [22]

I think is like 1.375

6 0
2 years ago
Read 2 more answers
Which of the following statements must be true based on the diagram below?(Diagram is not to scale.)FDEO EF is a segment bisecto
8_murik_8 [283]

From the diagram given;

ABCD is a quadrilateral;

Line |EF| bisects the line |AD| and line |CD|,

Thus, from the given options;

LINE |EF| is a segment bisector is the only correct option.

6 0
9 months ago
It was -5 degrees Celsius in Copenhagen and -12 degrees Celsius in Oslo. Which city was colder? *
PtichkaEL [24]

Answer: Oslo was colder

Step-by-step explanation: The other one was -5 and this won is -12 so Oslo is colder!! Hope it helped! :)

8 0
2 years ago
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