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2 years ago

Order of operations. Need to find the unknown number. Help?

Mathematics

2 answers:

klio [65]2 years ago

7 0

Answer:

m = 18

k = 4

g = 50

s = 18

y = 9

f = 19

Step-by-step explanation:

mamaluj [8]2 years ago

5 0

M = 18
K = 4
G = 42
S = 18
Y = 9
F = 19

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Amelie has 385 muffins that she must package into boxes. Each box must hold 9 muffins. Amelie divides 385 by 9 and gets an answe

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2nd one: amelia has 7 muffins left after filling 42 boxes

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2 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$

$e^{-0.01x} = 0.08$

$\ln{e^{-0.01x}} = \ln{0.08}$

$-0.01x = \ln{0.08}$

$x = -\frac{\ln{0.08}}{0.01}$

$x = 252.6$

Capacity of 252.6 cubic feet per second

5 0

3 years ago

WILL GIVE BRAINLIEST

Olegator [25]

The answer is A.
We can first eliminate D since it uses these (<, >) signs and the lines are shaded, indicating the points on those lines are solutions.
We can also eliminate C because the y intercept in C’s lines is 2, while in the graph, they are both 3.
Finally, we can look at both inequalities on the graph and see that the shaded areas are both underneath the line. This means that y is less than the equation for the line, eliminating B
So, the answer is A
Hope this made sense!!

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3 years ago

A coordinate plane with a line passing through (negative 4, 3), (0, 1), and (4, negative 1). Which linear function is represente

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Answer:

Step-by-step explanation:

If these 3 points are collinear, then we can find the slope of the linear function using any 2 of those points. Suppose we use (-4, 3) and (0, 1):

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Using the slope-intercept formula y = mx + b and replacing y with 1, x with 0 and m with -1/2, we get:

1 = (-1/2)(0) + b, or b = 1. Then the desired equation is y = f(x) = (-1/2)x + 1

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