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ASHA 777 [7]
3 years ago
10

Armando deposits $3,827 into a bank account paying 2.8% interest,

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

$745,460.8

Step-by-step explanation:

2.8/100 × 3827 = $107.16

monthly = 1/12

p =  \frac{100 \times i}{rt}  =  \frac{100 \times 107.16}{2.8 \times  \frac{1}{12} }  =  \frac{10716}{0.23}  \\ = 46591.3

$46,591.3 in 1year

16 years; $46,591.3 × 16 = $745,460.8

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A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
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Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

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The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

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E(C)=E(3X^{2}+X+2)

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Compute the expected value of <em>X</em> as follows:

E(X)=np

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The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

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The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

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E(C)=3E(X^{2})+E(X)+2

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Step-by-step explanation:

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