The answer is A; 1/2. You add 1 1/2 and 1 1/2 together to get 3. Then you subtract 3 1/2 and 3 to get your answer 1/2. I hope that helps!
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30+5=5+30 with commutative property or 30+5=35
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
C.E.: x <em>=/=</em> -4
Step-by-step explanation:
