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frosja888 [35]
2 years ago
7

Sven has $1 and a dime in his pile. Dayna has 11 dimes in her pile. If Sven gives Dayna $1 and Dayna gives Sven 10 dimes, will t

he two piles still be equal in value? Explain.
; The amounts that Sven and Dayna subtracted from their piles are . Therefore, the amounts left in the piles are .
Mathematics
1 answer:
viva [34]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Because a dollar and a dime and 11 dimes are equal in value ($1.10)

And they exchange 1 dollar and 10 dimes which is also the same amount. So they will be the same.

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Airida [17]

Answer:

x=8

Step-by-step explanation:

the addition of all the angles must equal 360(the 4 angles on the intersection) degrees

125+125=250

360-250=110

110/2=55

7*8-1=55

6 0
3 years ago
How would you factor this linear expression? 2x 6
ELEN [110]

2x-6

2(x-3)

therefore 2(x-3)=2x-6

3 0
3 years ago
Alan's go-kart travels 1750 feet per minute, and Barry's go-kart travels 21 miles perhour. Who's go-kart is faster? (There are 5
Igoryamba
I believe its Alan, because I multiplied 5,280x21 and got 15,840 and then I divided that by 60, and got 258. 258≤1750... so Alan is you're answer
6 0
3 years ago
Read 2 more answers
Radicales simples ……….
Alex

The expressions with radicals which are variables and numbers raised to a fractional indices are simplified as follows.

13. √(9·x)  = 3·√x

14. √(4·y) = 2·√y

15. √(8·x²) = 2·x·√2

16. √(9·x²) = 3·x

17. √(3·x²) = x·√3

18. √(5·y²) = y·√5

19. √(13·x²) = x·√(13)

20. √(29·y²) = y·√(29)

21. √(64·y²) = 8·y

22. √(125·a²) = 5·a·√5

23. ∛(16) = 2·∛2

24. √(50·a²·b) = 5·a·√(2·b)

<h3>What are radicals expressions?</h3>

A radical expression is one that contains the radical (square root or nth root) sign, √.

13. √(9·x)

√(9·x) = √(3²·x) = 3·√x

  • √(9·x)  = 3·√x

14. √(4·y)

√(4·y) = √(2²·y) = 2·√y

  • √(4·y) = 2·√y

15. √(8·x²)

√(8·x²) = √(4 × 2·x²) = √(2² × 2·x²)

√(2² × 2·x²) = √(2²·x² × 2) = 2·x·√2

  • √(8·x²) = 2·x·√2

16. √(9·x²)

√(9·x²) =  √(3²·x²) = 3·x

  • √(9·x²) = 3·x

17. √(3·x²)

  • √(3·x²) = x·√3

18. √(5·y²)

√5 × √(y²) = √5 × y = y·√5

  • √(5·y²) = y·√5

19. √(13·x²)

√(13·x²) = √(13) × √x² = √(13) × x = x·√(13)

  • √(13·x²) = x·√(13)

20. √(29·y²)

√(29·y²) = √(29) × √(y²) = √(29) × y = y·√(29)

  • √(29·y²) = y·√(29)

21. √(64·y²)

√(64·y²) = √(8²·y²) = √(8²) × √(y²) = 8 × y = 8·y

  • √(64·y²) = 8·y

22. √(125·a²)

√(125·a²) = √(25 × 5 × a²) = √(25) × √5 × √(a²) =  5 × √5 × a

5 × √5 × a  = 5·a·√5

  • √(125·a²) = 5·a·√5

23. ∛(16)

∛(16) = ∛(16) = ∛(8 × 2) =  ∛(2³ × 2) = 2·∛2

  • ∛(16) = 2·∛2

24. √(50·a²·b)

√(50·a²·b) = √(25 × 2 × a² × b) = √(5² × 2 × a² × b) = √(5² × a² × 2 × b)

√((5² × a²) × 2 × b) = 5·a·√(2·b)

  • √(50·a²·b) = 5·a·√(2·b)

Learn more about simplifying expressions with radicals here:

brainly.com/question/13114751

#SPJ1

5 0
1 year ago
Solve the system by elimination <br><br> 4x+3y=-5<br><br> -x+3y=-10
Sedaia [141]

Subtract the 2nd row from the 1st row

5x = 5

Solve for x in the equation above

x = 1

Substitute x = 1 into any of the two equations above

Let's  pick the first equation; 4x + 3y = -5

4 * 1 + 3y = -5

Solve for y in the equation above

y = -3

Therefore,

<u>x = 1</u>

<u>y = -3</u>

3 0
3 years ago
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