Answer:
Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Assemble all the data in one place, with molar masses above the formulas and other information below them.
Mᵣ: 58.44
NaCl + AgNO₃ ⟶ NaNO₃ + AgCl
m/g: 0.245
V/mL: 50.
c/mmol·mL⁻¹: 0.0180
2. Calculate the moles of each reactant
3. Identify the limiting reactant
Calculate the moles of AgCl we can obtain from each reactant.
From NaCl:
The molar ratio of NaCl to AgCl is 1:1.
From AgNO₃:
The molar ratio of AgNO₃ to AgCl is 1:1.
AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.
4. Calculate the moles of excess reactant
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
I/mmol: 0.900 4.192 0
C/mmol: -0.900 -0.900 +0.900
E/mmol: 0 3.292 0.900
So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.
5. Calculate the concentration of Cl⁻
The hybridization will be sp3. I hope that is helpful.
Answer:
D.<em>The</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>waves</em><em> </em><em>that</em><em> </em><em>pass</em><em> </em><em>a</em><em> </em><em>point</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>(</em><em>per</em><em>)</em><em> </em><em>second</em>
Answer:
Explanation:
Chemical equation:
HCl + Fe₂O₃ → FeCl₃ + H₂O
Balanced Chemical equation:
6HCl (aq)+ Fe₂O₃(s) → 2FeCl₃(aq) + 3H₂O(l)
Ionic equation:
6H⁺(aq) + 6Cl⁻(aq) + 2Fe⁺³(aq) + 3O²⁻(aq) → 2Fe⁺³(aq) + 6Cl⁻(aq) + 3H₂O(l)
Net ionic equation:
6H⁺(aq) + 3O²⁻(aq) → 3H₂O(l)
The Cl⁻(aq) and Fe⁺³(aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.