Two nitro (NO_2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but the
y can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO_2 group can have is required to be a multiple of epsilon, where epsilon = 1.0 times^-24 J. In other words, each NO_2 group could have epsilon of rotational kinetic energy, or 2 epsilon, or 3 epsilon, and so forth - but it cannot have just any old amount of rotational kinetic energy. Suppose the total rotational kinetic energy in this system is initially known to be 39 epsilon. Then, some heat is added to the system, and the total rotational kinetic energy rises to 59 epsilon. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.
1 answer:
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Answer: 2) 0.21 mole H2O
3) 0.50 mole K2O
4) 123 g Ca( NO3)2
Explanation: solution attached.
For number 2 to find the number of moles of H2O just divide the given in molecules with the Avogadro's number.
For 3 convert grams of K2O to moles by using 1 mole of K2O is equal to the molar mass of K2O
For number 4 moles to grams. Same process with number 3
