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Margaret [11]
3 years ago
13

Two nitro (NO_2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but the

y can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO_2 group can have is required to be a multiple of epsilon, where epsilon = 1.0 times^-24 J. In other words, each NO_2 group could have epsilon of rotational kinetic energy, or 2 epsilon, or 3 epsilon, and so forth - but it cannot have just any old amount of rotational kinetic energy. Suppose the total rotational kinetic energy in this system is initially known to be 39 epsilon. Then, some heat is added to the system, and the total rotational kinetic energy rises to 59 epsilon. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Chemistry
1 answer:
pantera1 [17]3 years ago
7 0

Answer:

Explanation:

The detailed and step by step analysis is as shown in the atached file with appropriate substitution.

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The differemt isotopes that differ in atomic mass

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It is an example of coupling an exogenic reaction to an endogenic reaction.

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How many atoms of lodine(I) are in 0.156 grams of I?
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A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.
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Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

m_1u_1+m_2u_2=m_1v_1+m_2v_2     ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of the first object.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

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Putting values in equation 1, we get:

80(0)+0.16(28)=(0.80+0.16)V

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The final velocity of man and hockey puck is 0.056 m/s.

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Explanation:

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