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Likurg_2 [28]
3 years ago
9

Help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
timofeeve [1]3 years ago
7 0
Its atmosphere!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Determine the potential deaths resulting from the following exposure to chlorine:
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Answer:

For each scenario as following:

A. 3 Potential deaths by chlorine exposure

B. 1 Potential deaths by chlorine exposure

C. 3 Potential deaths by chlorine exposure

Explanation:

According to Freitag, 1941 Chlorine exposure can be lethal at the concentration of 34-51 ppm in a time of 1h-1.5h. The answers are based on his reference.

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3 years ago
10 examples of<br>combination reaction​
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A rectangular metal bar has a volume of 50.0 in³. The bar weighs 1.42 kg. Calculate the density of the metal in
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You would do M divided by V= D and the answer is 0.0284
5 0
3 years ago
Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

Divide both side by 7.42

Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

Therefore, the mass of 6–Li is 6.018 amu

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3 years ago
A dad and his son are driving down the street then wreck, the dad died but the son has to go to the hospital because of his seri
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The doctor is His mom 
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