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tatiyna
2 years ago
14

Using the trend line y = 8x + 8, for the data shown, complete the residual table.

Mathematics
2 answers:
kkurt [141]2 years ago
6 0

-1,0,2,-2,0 :P

:)

:(

:O

Anit [1.1K]2 years ago
3 0

Answer:

-1,0,2,-2,0 in that order

Step-by-step explanation:

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if you can transfer to englis i may be able to help

Step-by-step explanation:

5 0
3 years ago
There are 12 boys in a math class. The total number of students s depends on the number of girls in the class g. write an equati
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3 years ago
Write the equation of a line perpendicular to 2x + 3y = 4 and passing through (-3,-5).
Tasya [4]

Answer:

Step-by-step explanation:

A line perpendicular to the given line has a slope that is the negative inverse of the reference line.  

Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.

2x + 3y = 4

3y=-2x+4

y = -(2/3)X + (4/3)

The reference slope is -(2/3).  The negative inverse is (3/2), which will be the slope of a perpendicular line.  We can write the new line as:

y = (3/2)x + b

Any value of b will still result in a line that is perpendicular.  But we want a value of b that will shift the line so that it intersects the point (-3,-5).  Simply enter this point in the above equation and solve for b.

y = (3/2)x + b

-5 = (3/2)(-3) + b

-5 = -(9/2) + b

-5 = -4.5 + b

b = - 0.5

The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is

y = (3/2)x - 0.5

6 0
1 year ago
What are the solutions to the equation?<br>x² + 3x - 54​
algol13

Answer:

x = - 9, x = 6

Step-by-step explanation:

Given

x² + 3x - 54

To find the solutions equate to zero

x² + 3x - 54 = 0 ← in standard form

(x + 9)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 6 = 0 ⇒ x = 6

7 0
3 years ago
Read 2 more answers
AB is the angle bisector of CAD. Solve for the missing variable?
Alika [10]

Answer:

x=8^\circ

Step-by-step explanation:

A bisector is the line that divides an angle (which in this case is \angle CAD) exactly in half. Therefore, \angle CAB = \angle BAD and as such we can solve for x:

\angle CAB &= \angle BAD\\33^\circ &= 4x + 1^\circ\\4x = 32^\circ\\x = 8^\circ

and we are done.

4 0
2 years ago
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