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BARSIC [14]
3 years ago
8

Please help me asap!! ​

Mathematics
1 answer:
Igoryamba3 years ago
3 0

Answer:

a) a reflection across the Y axis, then a translation 4 units down

b) for (x,y) -> (-x,y-4)

b)

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Harper knows he is 100 yards from school. The map on his phone shows that the school is 1/3 inch from his current location. If H
Anton [14]

Answer:

4 7/17 yeards or 4.412 yards approximately if the map shows the distance as 3 inches.

Step-by-step explanation:

The actual distance of the Harper from the school = 50 yards. According to the map, the distance from the school = 34 inches. We could say 34 inches represents 50 yards. So, 1 inch could be represented by 50/34 = 25/17 yards. In order to find the actual length of 3 inches in yards, we need to multiply 1 inches value of yards by 3.Therefore, 3 inches = 3* 25/17 = 75/17 = 4 7/17 yeards in decimals 4.412 yards approximately. Therefore,  Harper from home is  4 7/17 yeards or 4.412 yards approximately if the map shows the distance as 3 inches.

5 0
4 years ago
Given: 'y' varies directly with 'x' when k = 4/3
lesya [120]
Sue is correct.
When you plug in the values for x you find that Mark's answer for y should be 32/3 and Sue's answer for y should be 8 which is the answer she has.
4 0
3 years ago
Find the solutions please help me
weeeeeb [17]
The first one is:
y = 5-7=-2
(5, -2)

second one:
4 = x + 3
x =4-3=1
(1,4)
6 0
3 years ago
The perimeter of a square is 16a + 8. What is the length of one side?
LekaFEV [45]
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5 0
3 years ago
The map shows the route for a race.You are at X, 6000 ft from the first checkpoint C.The second checkpoint D is located at the m
Alex

Answer:

Distance between the two check point (C and D) is 4920 ft.

Step-by-step explanation:

From the question given above, we obtained the following information:

X is 6000 ft from C (1st check point)

D (2nd check point) is the midpoint point between C and Y ( the end of the race)

Total race = 3 miles

1 mile = 5280 ft

Next, we shall express the total race in feet (ft).

This is illustrated below:

1 mile = 5280 ft

Therefore,

3 miles = 3 × 5280 = 15840 ft

Next, we shall determine the distance between the 1st check point (C) and the end of the race (Y)

This can be obtained as follow:

Total distance = 15840 ft

Distance between X and C = 6000 ft

Distance between C and Y =?

Distance between C and Y = (Total distance) – (Distance between X and C)

Distance between C and Y = 15840 – 6000

Distance between C and Y = 9840 ft

Finally, we shall determine the distance between the two check point (C and D) as follow:

Since D is midpoint between C and Y, therefore, we shall we shall divide the distance between C and Y by 2 in order to obtain the distance between the two check point (C and D).

This is illustrated below:

Distance between C and Y = 9840 ft

Distance between the two check point (C and D) = 9840/2 = 4920 ft

Therefore, the distance between the two check point (C and D) is 4920 ft

5 0
3 years ago
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