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2 years ago

You ask only the members of your family that you can contact by phone what their favorite holiday is. Is this a census?

Mathematics

1 answer:

Maru [420]2 years ago

4 0

No, this would not be a census

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A swing set is going to be placed over a region of mulch that is shaped like a trapezoid. The bases of the trapezoid have a leng

matrenka [14]

Answer:

$114.8\ ft^{2}$

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

$A=\frac{1}{2}(b1+b2)h$

In this problem we have

$b1=12\ ft$

$b2=15\ ft$

$h=8.5\ ft$ ----> the height of the trapezoid is the perpendicular distance between the bases

substitute the values

$A=\frac{1}{2}(12+15)(8.5)$

$A=\frac{1}{2}(27)(8.5)=114.75\ ft^{2}$

Round to the nearest tenth

$114.75=114.8\ ft^{2}$

7 0

3 years ago

Read 2 more answers

1. An object is accelerated at a rate of 5 m/s²? Find the mass of the object if the force exerted on it is 4 x 10⁵dynes. (Note:

torisob [31]

Step-by-step explanation:

$\begin{gathered}\frak \red{Given}\:\begin{cases} \:\quad\sf Acceleration \:of \ \: a\:body\:,\:a\:=\:\pmb{\frak{5\:m/s^2\:}}\:\\ \:\quad\sf Force \:Exerted\:on\:a\:body\:,\:F\:=\:\pmb{\frak{\:4\times 10^5\: dynes\:}}\:\end{cases}\\\\\end{gathered}$

The mass of a body ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀

We're Provided with the , Acceleration (a) , and Force Exerted (F) on a body and , we'll find Mass (m) of the object using the relation

between Force , Mass & Acceleration  and, that is :

$\underline {\pmb{\sf \: F\:=\:m\:\times \:a \:}}$

$\\ \twoheadrightarrow \sf F \:=\:m\:\times \:a$

$: \rightarrow \sf 4 \:\times 10^5 \:=\:m\:\times \:5\:$

$\\ \\ \\ \\\twoheadrightarrow \sf 4 \:=\:m\:\times \:5\:\:\Bigg\lgroup \:1 \:N\:=\:1\:\times 10^5\:dynes\:\Bigg\rgroup\\$

$\\ \twoheadrightarrow \sf 4 \: \:=\:m\:\times \:5\:\\\\\\$

$\twoheadrightarrow \sf 5m\:=\:4\:\\$

$\twoheadrightarrow \sf m \cancel{\dfrac{4}{5}}\\\\$

$\ \twoheadrightarrow \pmb {\underline {\boxed {\purple {\:\frak{ \:m\:\:=\:0.8\:kg\:}}}}}\:\bigstar \: \\$

$\begin{gathered}\therefore \:\underline {\sf \: Hence,\:Mass\:of\:a\:body\:is\:\pmb{\sf 0.8\:kg\:}\:.}\:\\\\\end{gathered}$

8 0

2 years ago

An Indian tepee is a conical tent. Find the number of cubic feet of air in a teepee 10 ft. in diameter and 12 ft. high.

vampirchik [111]

Surface Area of a cone is

pi * r * s + pi * r^2 

s is the side length, since you have 10 ft diameter, you know radius is 5. And since height is 12. With this, you have a 5-12-13 triangle, and s=13. 

so 

pi * 5 * 14 + pi * 5^2 = 95 pi or 298.3 

divide 298.3 by 15 and you get 19.88, you round up, so 20 is the answer

5 0

3 years ago

What is the mean of the following set of data? Round your answer to two decimal places.

irinina [24]

Hope this helps but I think the answer is 5.14

6 0

3 years ago

Read 2 more answers

◆ Quadratic Equations ◆ Please help !

Mila [183]

I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

$\sf ax^2+(1-a(b+c))x+abc-d)$

$\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))$

Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

$\sf x^2+(1-5)x+2$

$\sf x^2-4x+2$

Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

$\sf x\approx\dfrac{4\pm 2.83}{2}$

$\sf x\approx 0.59,3.41$

So the answer would be A.

3 0

3 years ago