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olga nikolaevna [1]
3 years ago
13

Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th

e following box plots. Box plots titled Males versus Females in Hours Worked Weekly during the Summer with horizontal axis labeled Hours worked per week ranges from 0 to 55. Males box plot with minimum approximately at 15 and maximum approximately at 35 has interquartile range approximately between 20 and 25 and median approximately at 22. Females box plot with minimum at 0 and maximum approximately at 50 has interquartile range approximately between 0 and 25 and median is approximately at 20. Identify any values of data that may affect the statistical measures of center and spread.
Mathematics
2 answers:
kiruha [24]3 years ago
7 0

The biggest key here is identifying outliers. Outliers can pull measures of center either up or down drastically.Notice how the males have a VERY low outlier. This will pull the mean down severely and create a much larger range, or spread.The females have a median of about 12 hours, but have an upper extreme of 19, which compareatively is very high. This creates a larger range as well.

Elanso [62]3 years ago
4 0

Answer:

The females worked less than the males, and the female median is close to Q1.

Step-by-step explanation:

I took the test (;

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Answer:

\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

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Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

\sf \implies p(x)= - x^3+cx^2-4x+3 \\\\\implies\sf p(-3) = 0 \\\\\sf\implies -(-3)^3+c(-3)^2-4(-3)+3 = 0 \\\\\sf\implies 27 + 9c +12+3=0 \\\\\sf\implies 9c +42=0 \\\\\sf\implies 9c = (-42) \\\\\sf\implies c = \dfrac{-42}{9}\\\\\sf\implies \boxed{\pink{\sf c = \dfrac{-14}{3}}}

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