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Pavel [41]
3 years ago
7

Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.

Physics
1 answer:
exis [7]3 years ago
3 0
20c because te mass of the object is larger than the table
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PLEASE HELP WOULD REALLY APRECIATE IT THANKYOU :)
zzz [600]
Read through it carefully,

1400J of "heat" was added to the system

only 600J of thermal energy was added to the system, or only 600J of the "heat" was used to change the temperature

so if only 600 of 1400J was used to affect the temperature, that means the remaining heat energy must have been converted to work

1400J-600J =
4 0
4 years ago
Read 2 more answers
Consider the following three concentric systems two thick shells and a solid sphere all conductors The radii in the increasing o
Margarita [4]

Answer:

Explanation:

From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.

So, in light of that, to determine the electric charges values & signs on each of them, we have:

on a = +3 C

on b = -7 C

on c = -7 C

on d = +3 C

on e = -7 C

5 0
3 years ago
An alpha particle can be produced in certain radioactive decays of nuclei and consists of two protons and two neutrons. The part
Varvara68 [4.7K]

Answer:

Explanation:

charge, q = 2e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

mass, m = 4 u = 4 x 1.661 x 10^-27 kg = 6.644 x 10^-27 kg

Radius, r = 4.5 cm = 0.045 m

Magnetic field, B = 1.20 T

(a) Let the speed is v.

v=\frac{Bqr}{m}

v=\frac{1.20\times 3.2\times 10^{-19}\times 0.045}{6.644\times 10^{-27}}

v = 2.6 x 10^6 m/s

(b) Let T be the period of revolution

T=\frac{2\pi r}{v}

T=\frac{2\times 3.14\times 0.045}{2.6\times 10^{6}}

T = 1.09 x 10^-7 s

(c) The formula for the kinetic energy is

K=\frac{B^{2}\times q^{2}\times r^{2}}{2m}

K=\frac{\left ( 1.20\times 3.2 \times 10^{-19}\times 0.045 \right )^{2}}{2\times 6.644\times 10^{-27}}

K = 2.25 x 10^-14 J

(d) Let the potential difference is V.

K = qV

V = \frac{K}{q}

V= \frac{2.25\times 10^-14}{3.2\times 10^{-19}}

V = 70312.5 V

5 0
3 years ago
A baseball has a mass of 145 g. a bat exerts a force of 18,400 n on the ball. what is the acceleration of the ball? 1.27 x 102 m
fomenos

The acceleration of the ball is 1.27 X 10⁵ m/s²

The Newtons second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

Given,

Mass = 145 kg

Force = 18,400 N

We need to calculate the acceleration

Using formula of acceleration(a)

a = F/m  where F= force and m= mass

Put the values in the formula,

 a = 18,400/(145 X 10⁻³) = 1.27 X 10⁵ m/s²

Therefor, the acceleration of the ball is 1.27 X 10⁵ m/s².

Learn more about the Newton's second law with the help of the given link:

brainly.com/question/27573481

#SPJ4

7 0
2 years ago
A hockey puck slides off the edge of a table with an initial velocity of 23.2 m/s and experiences no air resistance. The height
Dennis_Churaev [7]

Answer:

15.1°

Explanation:

The horizontal velocity of the hockey puck is constant during the motion, since there are no forces acting along this direction:

v_x = 23.2 m/s

Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:

v_y(t)= v_{y0} -gt (1)

where

v_{y0}=0 is the initial vertical velocity

g = 9.8 m/s^2 is the gravitational acceleration

t is the time

Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by

h=\frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2.00 m)}{9.8 m/s^2}}=0.64 s

Substituting t into (1) we find the final vertical velocity

v_y = -(9.8 m/s^2)(0.64 s)=-6.3 m/s

where the negative sign means that the velocity is downward.

Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal:

tan \theta = \frac{|v_y|}{v_x}=\frac{6.3 m/s}{23.2 m/s}=0.272\\\theta = tan^{-1} (0.272)=15.1^{\circ}

6 0
3 years ago
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