Read through it carefully,
1400J of "heat" was added to the system
only 600J of thermal energy was added to the system, or only 600J of the "heat" was used to change the temperature
so if only 600 of 1400J was used to affect the temperature, that means the remaining heat energy must have been converted to work
1400J-600J =
Answer:
Explanation:
From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.
So, in light of that, to determine the electric charges values & signs on each of them, we have:
on a = +3 C
on b = -7 C
on c = -7 C
on d = +3 C
on e = -7 C
Answer:
Explanation:
charge, q = 2e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C
mass, m = 4 u = 4 x 1.661 x 10^-27 kg = 6.644 x 10^-27 kg
Radius, r = 4.5 cm = 0.045 m
Magnetic field, B = 1.20 T
(a) Let the speed is v.


v = 2.6 x 10^6 m/s
(b) Let T be the period of revolution


T = 1.09 x 10^-7 s
(c) The formula for the kinetic energy is


K = 2.25 x 10^-14 J
(d) Let the potential difference is V.
K = qV


V = 70312.5 V
The acceleration of the ball is 1.27 X 10⁵ m/s²
The Newtons second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
Given,
Mass = 145 kg
Force = 18,400 N
We need to calculate the acceleration
Using formula of acceleration(a)
a = F/m where F= force and m= mass
Put the values in the formula,
a = 18,400/(145 X 10⁻³) = 1.27 X 10⁵ m/s²
Therefor, the acceleration of the ball is 1.27 X 10⁵ m/s².
Learn more about the Newton's second law with the help of the given link:
brainly.com/question/27573481
#SPJ4
Answer:
15.1°
Explanation:
The horizontal velocity of the hockey puck is constant during the motion, since there are no forces acting along this direction:

Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:
(1)
where
is the initial vertical velocity
g = 9.8 m/s^2 is the gravitational acceleration
t is the time
Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by

Substituting t into (1) we find the final vertical velocity

where the negative sign means that the velocity is downward.
Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal:
