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4 years ago

9

A figure skater glides along a circular path of radius 3.42 m. If she coasts around one half of the circle, find the magnitude o

f the displacement vector.

1 answer:

dusya [7]4 years ago

3 0

Displacement is the distance between the start- and end-points,
no matter what route is followed from start to finish.

If she travels around half of the circle, then her start- and end-points
are the two ends of a diameter, and her displacement is its length.

The length of the diameter is (2 x radius) = 6.84 meters.

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A greater applied force is required to move an object with a greater mass than one with a smaller mass.

4vir4ik [10]

Answer:

True

Explanation:

The bigger an object is, the more force you must apply to move the object. Think about it like moving a mouse compared to moving an elephant. You can't move the elephant by yourself, because you don't have enough strength or force to move it. But, you can easily pick up a mouse, because it requires less force, or strength. Hope this helped :)

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3 years ago

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Which of the following is true concerning atoms?Atoms are made of even smaller substances called subatomic particles

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The correct answer of the given question above would be the first option. The statement that is true concerning atoms is that, atoms are made of even smaller substances called subatomic particles. Subatomic particles include neutrons, protons, electrons and atomic nuclei. Hope this answer helps.

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4 years ago

A spring required a force of 5.0 n to compress it 0.1 m. how much work is required to stretch the spring 0.4 m

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Answer:

20N

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4 years ago

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A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

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4 years ago

A sound wave has a wavelength of 1.32 m and travels at a speed of

kati45 [8]

Answer:

0.00377143

Explanation:

You would have to divide to get the frequency.

1.32/350 = 0.00377143

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

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3 years ago