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4 years ago

PLEASE HELP WOULD REALLY APRECIATE IT THANKYOU :)

Physics

2 answers:

zzz [600]4 years ago

4 0

Read through it carefully,

1400J of "heat" was added to the system

only 600J of thermal energy was added to the system, or only 600J of the "heat" was used to change the temperature

so if only 600 of 1400J was used to affect the temperature, that means the remaining heat energy must have been converted to work

1400J-600J =

Kisachek [45]4 years ago

3 0

The answer is 800J

the formula to find change in energy is:
heat - work = change in energy (your answer)

so to find the answer since you have the change in energy and the heat you would just minus the change in energy from the heat:)

to find this i just used the equation 1,400 - 600 = 800

I hope that made sense:)

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Read 2 more answers

A circular swimming pool has a diameter of 14 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Jo

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The work required is Wa = 2954112 J

Given:

swimming pool diameter = 14 m

length of sides = 4 m

height of water = 3 m

To Find:

work required to pump water

Solution: The radius of the swimming pool is

r = 14/2 = 7 m

The work is mathematically given as

W = Force x distance

Now force is mathematically given as

F = density x area x height of pool = p*(πr²)dx

Now the work done to pump all of the water over the side

W = ∫p*(πr²)(H-x)dx = ∫1000*9.81*(π*7^2)(4-x)dx

W = 64000*9.8π∫(4-x) dx = 64000*9.8π{4(3) - 3/2}

W = 2954112 J

So, work required is Wa = 2954112 J

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