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Pachacha [2.7K]
3 years ago
13

Determine if the point (4, -3) is a solution

Mathematics
1 answer:
Aneli [31]3 years ago
6 0
Not a solution I believe.
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On what interval(s) is the graph decreasing? - use interval notation
Anna [14]
The function is decreasing from -6 to -3, that is, on the interval (-6,-3), and again on the interval (1, infinity).  

The function is increasing on (-3,1).

No local or absolute minimum.

(1,4) is an absolute max.
6 0
4 years ago
How to find the power of area of a square 3.5² i know the answer is 12.25 but i want the formula of 3.5²​
LiRa [457]

Answer:

3.5^{2} = 3.5 * 3.5 = 12

square means: multiply the number <u>by itself</u> two times. so 3.5 * 3.5

cube (3.5^{3}) means: multiply the number by itself three times. so 3.5 * 3.5 * 3.5

i hope u understand :)

3 0
3 years ago
5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is
Dvinal [7]

Answer:

  x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

  m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

  m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

  \dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}

<h3>Solutions</h3>

The values of x that satisfy this equation are x = -2 and x = -9. The attached graphs show the lines for each of these cases.

4 0
1 year ago
How do you do equations.
Nesterboy [21]
Do you have a specific equation I can help you with. I can explain them better with a problem to look at?
7 0
4 years ago
Read 2 more answers
Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

5 0
3 years ago
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