Hexagon is a total of 6 triangle
Let find area of one triangle the multiplying with 6
Area of a triangle is A=1/2bh
We know b=6 and h= (6(square root of 3))/2
A= 1/2x6x(6(square root of3))/2=9(square root of 3)
Where square root of 3= 1.732
Area of a triangle=9x1.732 =15.588
Area of Hexagon equals 6 area of triangle so
Area of Hexagon= 6x 15.588=93.53
Answer:
The domain is all real numbers
Step-by-step explanation:
In any infinite quadratic equation, the domain is all real numbers.
The product of A and B matrix will be option D; BA = ![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C-6%26-6%26-19%5Cend%7Barray%7D%5Cright%5D)
.
<h3>What is the multiplication of matrix?</h3>
If ![A = \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
and ![B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
then,
BA = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
BA =
Hence, the product of A and B matrix will be option D; BA = .
Learn more about matrix here;
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Answer:
67.5cm^2
Step-by-step explanation:
area of a triangle is 0.5xaxb
