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3 years ago

How do you graph y=7

Mathematics

2 answers:

Damm [24]3 years ago

6 0

You go to x instead of y on a graph , find 7 and put a dot on it

zmey [24]3 years ago

4 0

I think the line y=7 would be the value 7 drawn across they-axis going horizontally

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For any perfect square trinomial (quadratic), the constant term (last term) must be positive.

Ronch [10]

Answer:

For the perfect square trinomial (quadratic) i.e. $\left(x\:+\:3\right)^2$ , the constant term (last term) is positive.

Step-by-step explanation:

"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.

For example:

$\left(x\:+\:3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$a=x,\:\:b=3$

$=x^2+2x\cdot \:3+3^2$

$=x^2+6x+9$

Therefore, for the perfect square trinomial (quadratic) i.e. $\left(x\:+\:3\right)^2$ , the constant term (last term) is positive.

5 0

3 years ago

ABCD Is a parallelogram if m

Viefleur [7K]

Step-by-step explanation:

ABC+DAB=180

DAB=180-115

DAB= 65

m<3+m<4=65

m<3=65-m<4

You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.

7 0

3 years ago

Read 2 more answers

You are researching the price of MP3 players. You found an average price of $58.80. One MP3 player costs $56 and another costs $

Butoxors [25]

The price of third MP3 player is $58.40

Step-by-step explanation:

Given,

Cost of one MP3 palyer = $56

Cost of another MP3 player = $62

Average price of MP3 player = $58.80

Let,

Cost of third MP3 player = x

Average = $\frac{Sum\ of\ costs}{Number\ of\ items}$

${58.80}=\frac{56+62+x}{3}$

Multiplying both sides by 3

$3*{58.80}=\frac{56+62+x}{3}*3\\176.40=118+x\\176.40-118=x\\58.40=x\\x=58.40$

The price of third MP3 player is $58.40

Keywords: average, division

Learn more about division at:

#LearnwithBrainly

8 0

3 years ago

Which of the following ordered pairs are solutions to the system of equations below?

spayn [35]

(3.583,-5.833) is your answer to the problem. because that is we’re they meet

7 0

3 years ago

N=4; 2i and 3i are zeros <br> f(-1)=50

Nonamiya [84]

Solution:- $\text{Let f(x) be any nth degree polynomial with n=4}\\$

$\text{Given that 2i and 3i are the zeroes of f(x)}$

$\text{so (x-2i) and (x-3i) are factors of f(x)}$

$\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}$

$\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)$

6 0

3 years ago